Answer:
the graph of f(x) is {5 - (-2)) units, or 7 units, higher than that of g(x)
Step-by-step explanation:
The vertex form of a quadratic equation is y = a(x - h)^2 + k. (h, k) represents the vertex.
Comparing the given f(x) = -3(x-1)^2 to the above general form, we see that h = 1 and k = 2.
Comparing the given g(x) = -3(x-1)^2 to the above general form, we see that h = 1 and k = -5.
Thus, the x-coordinates of the vertex in both cases are the same: 1. The y-coordinates differ: for f(x), k = 2. and for g(x), k = -5.
Changing the k value translates the graph up or down.
In this case we see that the graph of f(x) is {5 - (-2)) units, or 7 units, higher than that of g(x).
Y = 3x - 4 . . . (1)
9x - 3y = 14 . .(2)
Putting (1) into (2) gives
9x - 3(3x - 4) = 14
9x - 9x + 12 = 14
12 = 14
Therefore, there is no solution.
Answer:
Step-by-step explanation:
False
1) 2x+14=x+18
2x=x+4
x=4
2) 9y-2=3y+10
9y=3y+12
6y=12
y=2
3) 2*(2[4]+14) + (9[2]-2)
4) 32/2=16
5) 11*2=22
Answer:
20
Step-by-step explanation:
4x + 12x = 320
16x = 320
x = 320/16
x = 20