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Georgia [21]
3 years ago
12

X/z+y^2-x evaluate where x=-2 y=4 and z=16

Mathematics
1 answer:
lozanna [386]3 years ago
4 0

Answer:

Solution

X=-2

y=4

z=16

then,

-2/16+16×16--2

=257.875

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3 years ago
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jek_recluse [69]
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4 0
3 years ago
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lilavasa [31]
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EXAMPLE 3 Show that the curvature of a circle of radius k is 1/k. SOLUTION We can take the circle to have center the origin, and
Anastasy [175]

Answer:

Therefore r'(t) =-k sin t i + k cos t j and |r'(t)| = k so T(t) = r'(t)/|r'(t)| = -sin t i + cos t j  and T'(t) = -cos t i- sin t j . This gives |T'(t)| = 1, so using this equation, we have κ(t) = |T'(t)|/|r'(t)| = 1/k.

Step-by-step explanation:

We are already given the definition of curvature and the parametrization needed to find the curvature of the circle. In genecral the curvature κ is equal to κ(t)=|T'(t)|/|r'(t)| where r(t) is a parametrization of the curve and T(t) is the normalized tangent vector respect to the parametrization, that is, T(t)=r'(t)/|r'(t)|.

Now, using the derivatives of sines and cosines, and the definition of norm,  we obtain that:

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T(t) = r'(t)/|r'(t)|=-sin t i +cos t j ⇒ T'(t)= -cos t i - sin t j ⇒|T'(t)|²=cos²t+sin²t=1

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vladimir1956 [14]

Step-by-step explanation:

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