Answer:
![u=\frac{9}{t}-\frac{1}{2} a t](https://tex.z-dn.net/?f=u%3D%5Cfrac%7B9%7D%7Bt%7D-%5Cfrac%7B1%7D%7B2%7D%20a%20t)
Step-by-step explanation:
Step 1: Given equation: ![9=\frac{1}{2} a t^{2}+u t](https://tex.z-dn.net/?f=9%3D%5Cfrac%7B1%7D%7B2%7D%20a%20t%5E%7B2%7D%2Bu%20t)
To get u, by subtraction equality property subtract both sides of the equation by
.
Step 2: By division equality property, divide both sides of the equation by t.
![\Rightarrow \frac{9-\frac{1}{2} a t^{2}}{t}=\frac{u t}{t}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cfrac%7B9-%5Cfrac%7B1%7D%7B2%7D%20a%20t%5E%7B2%7D%7D%7Bt%7D%3D%5Cfrac%7Bu%20t%7D%7Bt%7D)
Therefore,
.
So, in Emily’s physics class, she got
.
Answer
Find out the how many pounds of metal are in 1,950 lb of ore .
To proof
let us assume that the pounds of metal are in 1,950 lb of ore be x .
As given
In an ore, 9.8% of its total weight is metal.
ore weight = 1,950 lb
9.8% is written in the decimal form
![= \frac{9.8}{100}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B9.8%7D%7B100%7D)
= 0.098
Than the equation becomes
x = 0.098 × 1950
x = 191.1 pounds
Therefore the 191.1 pounds of metal are in 1,950 lb of ore .
Hence proved
A because linear means straight line
5/54 this should be your answers hope this helps