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olganol [36]
3 years ago
8

Explain how solving -7y > 161 is different from solving 7y > -161. Please and thank you :D

Mathematics
2 answers:
padilas [110]3 years ago
8 0
-7y > 161......here, u would divide both sides by -7...keep in mind, when dividing/multiplying by a negative number, the inequality sign changes.
y < 161/-7
y < -23

7y > -161...here u divide by 7
y > -161/7
y > -23
aivan3 [116]3 years ago
8 0

Both inequalities use the division property to isolate the variable, y. When you divide by a negative number, like –7, you must reverse the direction of the inequality sign. When you divide by a positive number, like 7, the inequality sign stays the same. The solution to the first inequality is y > -23, and the solution to the second inequality is y <>

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Artemon [7]

Hey there! I'm happy to help!

We want to figure out what x is. Let's use a trigonometric ratio of our 35 degree angle to find it.

We see that x is opposite of the 35 degree angle. We also see that our hypotenuse 4.1 m. The hypotenuse is always across from the right angle.

The trigonometric ratio that deals with opposite and hypotenuse is the sine, which is the opposite divided by the hypotenuse. This gives us the following equation.

sin35=\frac{x}{4.1}

We want to solve for x, so we simply multiply both sides 4.1

x=4.1(sin35)

If we evaluate this on our calculators, we get 2.351663389......

We round this to the nearest tenth, giving us 2.4 m.

Have a wonderful day! :D

6 0
3 years ago
Which of the following is true of the location of an angle, Theta, whose tangent value is Negative StartFraction StartRoot 3 End
Anuta_ua [19.1K]

The value of theta has a 30-degree reference angle and is located in Quadrant II or IV.

Given to us

tan \theta =-\dfrac{\sqrt{3}}{3}

<h3>What is the value of tan \theta =\dfrac{\sqrt{3}}{3}?</h3>

To know the value  tan \theta =\dfrac{\sqrt{3}}{3} we will simplify the given expression,

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Hence, the value of theta is 30°.

<h3>Finding the location of the - tan30°?</h3>

To know that the location of the -tan30°,

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As the value is negative, therefore, there can be two cases,

Case I: when the value of Sin30° is negative,

Case II: when the value of cos30° is negative.

Case I: when the value of Sin30° is negative,

If the value of Sin30° is negative, while the value of cos30° is positive, the θ will lie in the fourth quadrant.

Case II: when the value of Cos30° is negative,

If the value of Cos30° is negative, while the value of Sin30° is positive, the θ will lie in the second quadrant.

Hence, the value of theta has a 30-degree reference angle and is located in Quadrant II or IV.

Learn more about Quadrants:

brainly.com/question/350459

5 0
3 years ago
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Virty [35]

Answer:

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8 0
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8 0
4 years ago
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/// hope this help!
5 0
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