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Travka [436]
2 years ago
15

Find the volume and round to the nearest tenth as needed

Mathematics
1 answer:
monitta2 years ago
3 0

Answer: 1962.4 cubic mm

Step-by-step explanation:

The volume of the larger cone is V=\frac{1}{3}(\pi)(10^{2})(20)=\frac{2000\pi}{3}

The volume of the smaller cone is V=\frac{1}{3}(\pi)(3^{2})(14)=42\pi.

So, the volume is \frac{2000\pi}{3}-42\pi \approx \boxed{1962.4}

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3 years ago
Convert 4.08 to a fraction.<br><br> Help me please.
Fofino [41]

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4/8

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2 years ago
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2 years ago
Solve each equation using the quadratic formula. Find the exact solution, then approximate the solution to the nearest hundredth
Anika [276]

Answer:

x_1=\frac{5+\sqrt{33}}{4}≈2.69

x_2=\frac{5-\sqrt{33}}{4}≈-0.19



Step-by-step explanation:

 To solve this problem you  must apply the proccedure shown below:

1. You have that the quadratic formula is:

x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}

2. To solve the quadratic equation you must substitute the values. So, you have that:

Rewrite the equation:

2x^{2}-5x-1=0

a=2\\b=-5\\c=-1

Then you have:

 x=\frac{-(-5)+/-\sqrt{(-5)^{2}-4(2)(-1)}}{2(2)}

3. Therefore, you obtain the following result:

x_1=\frac{5+\sqrt{33}}{4}≈2.69

x_2=\frac{5-\sqrt{33}}{4}≈-0.19


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C

Step-by-step explanation:

the proof of the answer is seen in the diagram

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