If we were to plot the points on a graph, we could draw a straight lint between them. The question wants us to find the length of this line. We could make a right triangle with this line as the hypotenuse, with an x length of 2(y2-y1) and a y length of 5 (y2-y1). From there we can find the hypotenuse with Pythagorean Theorem: c^2=a^2+b^2.
c^2=(2)^2+(5)^2
c^2=4+25
C^2=41
c=
Decimal approximation: 6.403
Hope this helps!
Answer:
Step-by-step explanation:
Given
Required
Equivalent form of the first equation that eliminates x when added to the second
To do this, we simply make the coefficients of x to be opposite in both equations.
In the second equation, the coefficient of x is 8.
So, we need to make the coefficient of x -8, in the first equation.
Multiply by -10
![-10 * [\frac{4}{5} x-\frac{3}{5}y=18]](https://tex.z-dn.net/?f=-10%20%2A%20%5B%5Cfrac%7B4%7D%7B5%7D%20x-%5Cfrac%7B3%7D%7B5%7Dy%3D18%5D)
<em>When this is added to the first equation, the x terms becomes eliminated</em>
Answer:
very less
Step-by-step explanation:
When rolling a fair 6 sided die 5 times there are 6^5 possible combinations.
Of those, there are 5 ways to roll exactly four sixes, and each of those ways have 5 possible results on the die which has not rolled a six, plus there is 1 way to roll five sixes. 5*5+1=26 combinations with at least four sixes.
Now, take the number of results which fit your conditions, divide by the number of possible results and you get your answer: 26/7776 which can be reduced to 13/3338, a bit less than 0.4%
I think it’s the first one
Sorry if I’m wrong
Where is the graph?.........
