PLEASEEEEEEEE!!!!! I need help ASAP

Mathematics

2 answers:

Elis [28]3 years ago

6 0

Hello!

A, and C

B is just a number. D is a term. anything with an equal sign is considered a mathematical equation/sentence

I hope this helps, and have a nice day!

MA_775_DIABLO [31]3 years ago

3 0

Answer:

The answers are A and C

Step-by-step explanation:

A and C are correct mathematical sentences.

B is just a coefficient

Also D is simply the factor of 2 and x or twice a number but not a sentence.

Hope this helps. Que, brainliest is appreciated if I have earned it.

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lina2011 [118]

To find the median, place the given numbers in order of their value and find the middle number.

Here we have:

57, 61, 58, 54, 68, 51, 49, 64, 50, 48, 65, 52, 56, 46, 47, 55, 42, 60, 62, 43, 69, and 70.

Arranging them in order from least to greatest, we have:

42, 43, 46, 47, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 61, 62, 64, 65, 68, 69, and 70.

There are 22 numbers total; the median will be the mean of the middle two numbers, which are 55 and 56.

To find the mean, add the numbers together and divide the sum by 2.

55 + 56 = 111

111 / 2 = 55.5

The median of the ages of the US Presidents at the time of their inauguration is 55.5 years.

5 0

3 years ago

How do i graph y=1/2Sinø/2?

podryga [215]

$\fb \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}
\end{array}
\\\\
-------------------$

$\bf \bullet \textit{ stretches or shrinks}\\
\left. \qquad \right. \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}$

$\bf \bullet \textit{function period or frequency}\\
\left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)$

now, with that template in mind,

$\bf \stackrel{parent~function}{y=sin(\theta )}\qquad \qquad y=\stackrel{A}{\frac{1}{2}}sin\left(\stackrel{B}{\frac{1}{2}}\theta \right)
\\\\\\
Amplitude\implies \frac{1}{2}
\\\\\\
Period\implies \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{1}{2}}\implies 4\pi$

which is pretty much the same sin(θ) function, but squished by 1/2 and elongated up to 4π, check the picture below.