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natita [175]
3 years ago
12

What is the probability that 6 rolls of a fair die will show four exactly 5 times?

Mathematics
1 answer:
storchak [24]3 years ago
6 0

Answer:

very less

Step-by-step explanation:

When rolling a fair 6 sided die 5 times there are 6^5 possible combinations.

Of those, there are 5 ways to roll exactly four sixes, and each of those ways have 5 possible results on the die which has not rolled a six, plus there is 1 way to roll five sixes. 5*5+1=26 combinations with at least four sixes.

Now, take the number of results which fit your conditions, divide by the number of possible results and you get your answer: 26/7776 which can be reduced to 13/3338, a bit less than 0.4%

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129 degrees you just add DCE and ECF together
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A sequence is defined recursively by the formula f(n+1) =f(n) + 3 the first term of the sequences is -4 what is the next term in
MArishka [77]
-1 would be your answer. f(0) = -4. f(1) = f(0)+3 so f(1) = -1
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Brad is having a party and buys a large cube of cheddar cheese at the market. The cube is 4 inches in height. When Brad gets hom
Naddika [18.5K]

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32 cubic inches

Step-by-step explanation:

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3 0
3 years ago
adiocarbon dating of blackened grains from the site of ancient Jericho provides a date of 1315 BC ± 13 years for the fall of the
Zigmanuir [339]

Answer:

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659 and \left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

Step-by-step explanation:

The equation of the isotope decay is:

\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }

14-Carbon has a half-life of 5568 years, the time constant of the isotope is:

\tau = \frac{5568\,years}{\ln 2}

\tau \approx 8032.926\,years

The decay time is:

t = 1315\,years + 2007\,years \pm 13\,years (There is no a year 0 in chronology).

t = 3335 \pm 13\,years

Lastly, the relative amount is estimated by direct substitution:

\frac{m(t)}{m_{o}} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\mp\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{-\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{min} \approx 0.659

\left(\frac{m(t)}{m_{o}} \right)_{max} = e^{-\frac{3335\,years}{8032.926\,years} }\cdot e^{\frac{13\,years}{8032.926\,years} }

\left(\frac{m(t)}{m_{o}} \right)_{max} \approx 0.661

4 0
3 years ago
you only have to answer one, dont answer one thats been answered. also english please im a baby who wont learn new languages.
shepuryov [24]

Answer:

1. x=11

Step-by-step explanation:

2x+5=27

Subtract 5 from both sides

2x=22

Divide 2 from both sides

x=11

4 0
3 years ago
Read 2 more answers
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