F(x)= x² + 8
When x = 10
f(x) = 10² + 8 = 108
Answer: 108
3.2-5.7=-2.5 so its have to be a negative because a smaller number subtract a bigger number have to be equal to a negative number.
Answer:
We can make maximum 16 bracelets .
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Well obviously quarters equal 25 cents. So you have to divide the 8.85 by 25 first. That means he could have 35 quarters. That least the rest as being dimes. So find the remaining amount of the 8.85. If you have 35 quarters that's $8.75. And 8.85 minus 8.75 is 10 cents. which would be 2 nickels. That only adds up 37 coins. So you break down one of the 25. That would mean 5 more coins could be nickels. Add 37 and 5 to get 42. Do it again. 25 cents in nickels would be 5 more coins. would be 46. that would be missing 2 coins. But don't forget you're also subtracting from the 35 quarters. Now you would technically have 12 nickels and 33 quarters. So you can do it one more time. 32 quarters means there is $8 in quarters at this point.
Now add you have 12 nickels, and you made 5 more. That's 17 nickels. That equals 85 cents. So add 17 and 32 to be sure you have 49 coins, which you do.
So 17 nickels, 32 quarters to equal 49 coins and $8.85
(sorry some of it got mixed up above because I was forgetting to subtract the quarters from the total as I changed them to nickels, so pay attention to the end)
Part A:
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by

The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
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