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alexdok [17]
3 years ago
9

An audiologist is testing a patient to determine the softest sound of a specific frequency that the patient reports hearing. She

begins with a 10 decibel (dB) sound for trial 1, then increases the volume by 2 dB for each trial after that. If the patient can hear all sounds of that frequency that have a volume louder than 26 dB, and t represents the trial numbers that the patient can hear, which of the following inequalities best models the situation described above?
Mathematics
1 answer:
den301095 [7]3 years ago
5 0

Answer:

26 <t+2

Step-by-step explanation:

The volume has to be louder than 26 so the inequaltiy sign should be an x is greater than sign and the intervals increase by 2 so you can add 2 to each x.

Hope this helps!

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givi [52]

Answer:

2/7 + (-3/4) + (-2/7) + 4/3

If we look at 2/7 and (-2/7), we can see that both of them combined will get you a result of 0, so let's do that first.

2/7 + (-2/7) = 0

Now we're left with;

(-3/4) + 4/3

Make sure to convert both fractions into having a common denominator,

[They both have a common denominator of 12], so:

(-3/4) = (-9/<u>12</u>)

4/3 = 16/<u>12</u>

Add them:

(-9/12) + 16/12

16/12 - 9/12

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