The y intercept is 0.5 because thats where the line starts.
the slope/gradient of the line is 1.5.
this would be written in the form: y=1.5x+0.5
Sallys statement is always true
for example:
-6 + 2 = -4
but if I turn it around
2 - 6 = -4
same answer
-6 -6 = -12
swap around -6 - 6 = 12
same answer
again -3 + 6 = 3
and 6 - 3 = 3
a. Length of the fence around the field = perimeter of quarter circle = 892.7 ft.
b. The area of the outfield is about 39,584 sq. ft..
<h3>What is the Perimeter of a Quarter Circle?</h3>
Perimeter of circle = 2πr
Perimeter of a quarter circle = 2r + 1/4(2πr).
a. The length of the fence around the field = perimeter of the quarter circle fence
= 2r + 1/4(2πr).
r = 250 ft
Plug in the value
The length of the fence around the field = 2(250) + 1/4(2 × π × 250)
= 892.7 ft.
b. Size of the outfield = area of the full field (quarter circle) - area of the infield (cicle)
= 1/4(πR²) - πr²
R = radius of the full field = 250 ft
r = radius of the infield = 110/2 = 55 ft
Plug in the values
Size of the outfield = 1/4(π × 250²) - π × 55²
= 49,087 - 9,503
= 39,584 sq. ft.
Learn more about perimeter of quarter circle on:
brainly.com/question/15976233
Answer:
B. - 4x - 5
Step-by-step explanation:
(p о n) (x) is the same thing as (p(n(x))
We know n(x) = x - 5, so let's input that into our expression
(p(x - 5))
Since we know p(x) = x^2 + 6x, let's replace the x with the new value x-5. Now our expression is:
p(x) = (x - 5)^2 + 6(x - 5)
Now all we have to do is simplify.
(x - 5)^2 is the same as: (x - 5)(x - 5)
Using the foil method, it simplifies to: x^2 - 10x + 25
6 (x - 5) = 6x - 30
Now our expression is: x^2 - 10x + 25 + 6x - 30
Combine like terms: x^2 - 4x - 5
The expression is: - 4x - 5
Answer:
f(w) = 3w + 2,000,000/w
Step-by-step explanation:
We know that the area of a rectangle is the product of its length and width:
A = LW
Filling in the given values lets us write an expression for the length of the field.
1,000,000 = Lw
L = 1,000,000/w
Since there are 3 fences of length w and two of length L, the total perimeter fence length is the sum ...
f(w) = 3w + 2(1,000,000)/w
Combining the constants, we have a function for the perimeter fence length in terms of the width of the field:
f(w) = 3w +2,000,000/w