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Korvikt [17]
3 years ago
12

Last​ year, a person wrote 123 checks. Let the random variable x represent the number of checks he wrote in one​ day, and assume

that it has a Poisson distribution. What is the mean number of checks written per​ day? What is the standard​ deviation? What is the​ variance?
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
3 0

Answer:The mean number of checks written per​ day = 0.3370

The standard deviation = 0.5805

The variance = 0.3370

Step-by-step explanation:

Let the random variable x represent the number of checks he wrote in one​ day.

Given : The number of checks written in last year = 123

Let the number of days in the year must be 365.

Now, the mean number of checks written per​ day will be  :-

\lambda=\dfrac{123}{365}=0.33698630137\approx0.3370

We know that in Poisson distribution , the variance is equals to the mean value .

\text{Thus , Variance }=\sigma^2= 0.3370

\Rightarrow\ \sigma=\sqrt{0.3370}=0.580517010948\approx0.5805

Thus,  Standard deviation = 0.5805

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*the scatter plot of the question is attached below

Answer:

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Step-by-step explanation:

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We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

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