The probability that the spinner lands on an even number or on the unshaded section is; 3/5
<h3>How to find the probability?</h3>
From the spinner attached, we see that the number of sections on the spinner is 5 sections.
Now, we can also see that;
Number of even numbers section = 2
Number of shaded sections = 1
Thus, probability that the spinner lands on an even number or on the unshaded section is;
P(even number or unshaded section) = (2 + 1)/5 = 3/5
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Answer:
<em>n</em> - <em>k</em> + 1
Step-by-step explanation:
This is assuming (because you did not say) that <em>n</em> and <em>k</em> are integers and <em>n</em> is greater than <em>k</em>.
Example: from 2 to 5 {2, 3, 4, 5} includes 5 - 2 + 1 = 4 numbers.
Example: from -6 to 4 includes 4 - (-6) + 1 = 11 numbers, namely {-6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4}
Answer:
The cost of one pass is 25$
Step-by-step explanation:
Call the cost of one of the passes, P. So we have
63 = 13 + 2P - subtract 13 from both sides
50 = 2P - divide both sides by 2
25 = P
So the cost of one pass = $25