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kobusy [5.1K]
3 years ago
6

225125 in base 6 divided by 101 in base 6​

Mathematics
1 answer:
myrzilka [38]3 years ago
4 0

225125₆/101₆ = 2225₆

One way to arrive at this is to convert both given numbers to base 10, compute the quotient in base 10, then convert back to base 6.

101₆ = 1×6² + 0×6¹ + 1×6⁰ = 37

225125₆ = 2×6⁵ + 2×6⁴ + 5×6³ + 1×6² + 2×6¹ + 5×6⁰ = 19,277

So we have

225125₆/101₆ = 19,277/37 = 521

Next,

521 = 2×216 + 89 = 2×6³ + 89

89 = 2×36 + 17 = 2×6² + 17

17 = 2×12 + 5 = 2×6¹ + 5×6⁰

and so

521 = 2×6³ + 2×6² + 2×6¹ + 5×6⁰ = 2225₆

Or you can use the long division algorithm. Division in base 6 is the same as in base 10, except numerals range from 0 to 5 instead of 0 to 9. See if you can follow this diagram (replaced with an attachment)

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Check the picture below.

\bf \left. \qquad  \right.\textit{internal division of a line segment}
\\\\\\
a(-1,2)\qquad b(7,14)\qquad
\qquad 1:3
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\cfrac{aP}{Pb} = \cfrac{1}{3}\implies \cfrac{a}{b} = \cfrac{1}{3}\implies 3a=1b\implies 3(-1,2)=1(7,14)
\\\\
-------------------------------\\\\
{ P=\left(\cfrac{\textit{sum of "x" values}}{r1+r2}\quad ,\quad \cfrac{\textit{sum of "y" values}}{r1+r2}\right)}

\bf -------------------------------\\\\
P=\left(\cfrac{(3\cdot -1)+(1\cdot 7)}{1+3}\quad ,\quad \cfrac{(3\cdot 2)+(1\cdot 14)}{1+3}\right)
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3 0
3 years ago
What is the probability that the spinner lands on an even number or on the unshaded section? one-fifth two-fifths three-fifths f
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The probability that the spinner lands on an even number or on the unshaded section is; 3/5

<h3>How to find the probability?</h3>

From the spinner attached, we see that the number of sections on the spinner is 5 sections.

Now, we can also see that;

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Thus, probability that the spinner lands on an even number or on the unshaded section is;

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Read more about Probability at; brainly.com/question/24756209

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2 years ago
How many numbers are from k to n? (Including k and n.)
shepuryov [24]

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Step-by-step explanation:

This is assuming (because you did not say) that <em>n</em> and <em>k</em> are integers and <em>n</em> is greater than <em>k</em>.

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Example: from -6 to 4 includes 4 - (-6) + 1 = 11 numbers, namely {-6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4}

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The cost of one pass is 25$

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Call the cost of one of the passes, P.   So we have

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