U(x) = f(x).(gx)
v(x) = f(x) / g(x)
Use chain rule to find u(x) and v(x).
u '(x) = f '(x) g(x) + f(x) g'(x)
v ' (x) = [f '(x) g(x) - f(x) g(x)] / [g(x)]^2
The functions given are piecewise.
You need to use the pieces that include the point x = 1.
You can calculate f '(x) and g '(x) at x =1, as the slopes of the lines that define each function.
And the slopes can be calculated graphycally as run / rise of each graph, around the given point.
f '(x) = slope of f (x); at x = 1, f '(1) = run / rise = 1/1 = 1
g '(x) = slope of g(x); at x = 1, g '(1) = run / rise = 1.5/ 1 = 1.5
You also need f (1) = 1 and g(1) = 2
Then:
u '(1) = f '(1) g(1) + f(1) g'(1) = 1*2 + 1*1.5 = 2 + 1.5 = 3.5
v ' (x) = [f '(1) g(1) - f(1) g(1)] / [g(1)]^2 = [1*2 - 1*1.5] / (2)^2 = [2-1.5]/4 =
= 0.5/4 = 0.125
Answers:
u '(1) = 3.5
v '(1) = 0.125
Answer:
O f(x) = 2x3 – x+4 and g(x) = -2x + x - 6
Step-by-step explanation:
The ordered pair that is a solution of the system is (-2, 8).
<h3>Which ordered pair is included in the solution set to the following system?</h3>
Here we have the system of inequalities:
y > x² + 3
y < x² - 3x + 2
To check which points are solutions of the system, we can just evaluate both inequalities in the given points and see if they are true.
For example, for the first point (-2, 8) if we evaluate it in the two inequalities we get:
8 > (-2)² + 3 = 7
8 < (-2)² - 3*(-2) + 2 = 12
As we can see, both inequalities are true. So we conclude that (-2, 8) is the solution.
(if you use any other of the 3 points you will see that at least one of the inequalities becomes false).
If you want to learn more about inequalities:
brainly.com/question/18881247
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