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Lorico [155]
3 years ago
9

Find the area enclosed by the figure. Use 3.14 for π. (The figure is not to scale).​

Mathematics
2 answers:
alekssr [168]3 years ago
7 0

Answer:

First let's find the area of the right triangle on the left side. To do that, multiply 6x5, then divide the product by 2, since a right triangle is half a rectangle.

6x5=30

30/2=15

gtnhenbr [62]3 years ago
3 0

Answer:

97.27 yd²

Step-by-step explanation:

First let's find the area of the right triangle on the left side. To do that, multiply 6x5, then divide the product by 2, since a right triangle is half a rectangle.

6x5=30

30/2=15

Area of triangle=15 yd²

Find area of the middle rectangle. So multiply the length by the width.

9x6=54

Area of rectangle=54 yd²

Find area of the half circle. Formula for area of circle is A=\pi r^{2}. Pi is about 3.14, and radius (r) is 3. Radius is half of the diameter of circle, and the 6 on the left says the diameter of circle.

\pix3^{2}≈28.27

Area of circle is about 28.27 yd²

Add up the three areas.

15+54+28.27=97.27

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Answer:

The answer is the first graph.

Step-by-step explanation:

I did it on edge. I got it wrong the first time because I used an answer from this question. Because of that, I reported it. Now I have the correct answer lol.

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the perimeter of a rectangular field is (16a+8b-6c) units and one of its side is (5a+3b-4c) find the other side
Jet001 [13]

3a+b+c


The perimeter is two times one side (to account for the opposite) and two times the adjacent side. So if the sides would be x and y, the perimeter would be 2*x + 2*y.

So, knowing that the sum is 16a+8b-6c, if we subtract the given side 5a+3b-4c from this, what remains is two times the "other" side:

16a+8b-6c - 2*(5a+3b-4c) =

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