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Evgesh-ka [11]
3 years ago
5

Algebra 2(8x2-7)+(8-8x2)

Mathematics
2 answers:
Katarina [22]3 years ago
6 0
The answer is just 1 l, just didn’t on the top of my head.
Leviafan [203]3 years ago
5 0
Remember to use the PEMDAS order of operations which states that you need to do the following in the order posted...

Parenthesis
Exponents
Multiplication and Division
Addition and Subtraction

All from the left to right.

So 8x2=16-7=9
Then
8x2=16....8-16=-8

9+-8=1
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Solve the following System of Three Equations: x−3y+z=−15<br> 2x+y−z=−2<br> x+y+2z=1
jeyben [28]

Answer:

x = -3 , y = 4 , z = 0

Step-by-step explanation:

Solve the following system:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for z:

{x - 3 y + z = -15

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Solve for z.

Subtract x - 3 y from both sides:

{z = 3 y + (-x - 15)

2 x + y - z = -2

x + y + 2 z = 1

Hint: | Perform a substitution.

Substitute z = -15 - x + 3 y into the second and third equations:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

x + y + 2 (-15 - x + 3 y) = 1

Hint: | Expand the left hand side of the equation x + y + 2 (-15 - x + 3 y) = 1.

x + y + 2 (-15 - x + 3 y) = x + y + (-30 - 2 x + 6 y) = -30 - x + 7 y:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for x:

{z = -15 - x + 3 y

15 + 3 x - 2 y = -2

-30 - x + 7 y = 1

Hint: | Isolate terms with x to the left hand side.

Subtract 15 - 2 y from both sides:

{z = -15 - x + 3 y

3 x = 2 y - 17

-30 - x + 7 y = 1

Hint: | Solve for x.

Divide both sides by 3:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

-30 - x + 7 y = 1

Hint: | Perform a substitution.

Substitute x = (2 y)/3 - 17/3 into the third equation:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Choose an equation and a variable to solve for.

In the third equation, look to solve for y:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 - 73/3 = 1

Hint: | Isolate terms with y to the left hand side.

Add 73/3 to both sides:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

(19 y)/3 = 76/3

Hint: | Solve for y.

Multiply both sides by 3/19:

{z = -15 - x + 3 y

x = (2 y)/3 - 17/3

y = 4

Hint: | Perform a back substitution.

Substitute y = 4 into the first and second equations:

{z = -x - 3

x = -3

y = 4

Hint: | Perform a back substitution.

Substitute x = -3 into the first equation:

{z = 0

x = -3

y = 4

Hint: | Sort results.

Collect results in alphabetical order:

Answer: {x = -3 , y = 4 , z = 0

6 0
3 years ago
SOMEONE PLEASE HELP ME OUT THIS IS DUE In 20 MINUTES (PICTURE)
notka56 [123]
9ths answer. 113.112 ~ 113.1
8 0
3 years ago
Determine the factors of x2 − 7x − 10. (5 points) a (x + 2)(x − 5) b Prime c (x − 2)(x + 5) d (x + 10)(x − 1)
Savatey [412]

For this case we must factor the following expression:

x ^ 2-7x-10

To factor, we must find two numbers that when added together give -7 and when multiplied by -10.

It is observed that there are not two whole numbers that comply with the aforementioned.

Thus, the following equation applies:

x = \frac {-b \pm\sqrt{b ^ 2-4 (a) (c)}} {2 (a)}

Where:

a = 1\\b = -7\\c = -10

We replace:

x = \frac {- (- 7) \pm \sqrt {(- 7) ^ 2-4 (1) (- 10)}} {2 (1)}\\x = \frac {7 \pm \sqrt {49 + 40}} {2}\\x = \frac {7 \sqrt {89}} {2}

So, the roots are:

x_ {1} =\frac {7+ \sqrt {89}} {2}\\x_ {2} =\frac {7- \sqrt {89}} {2}

Answer:

x_ {1} =\frac {7+ \sqrt {89}} {2}\\x_ {2} =\frac {7- \sqrt {89}} {2}

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3 years ago
I catfished someone and I was being so nice I don’t think I’ve ever been that nice to someone the point is that imma Kermit (mem
Katyanochek1 [597]
Omg don’t catfish it’s so damaging to your own self confidence!
4 0
4 years ago
Use the Distributive Property <br> 8(3x+2)
MA_775_DIABLO [31]

Answer:24x+16

Step-by-step explanation:

8 0
3 years ago
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