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ololo11 [35]
3 years ago
15

What type of information do you need to be given to prove two triangles are congruent? ​

Mathematics
1 answer:
marusya05 [52]3 years ago
5 0

If the hypotenuse and leg of one right triangle are congruent to the corresponding parts of another right triangle, the right triangles are congruent. The "included angle" in SAS is the angle formed by the two sides of the triangle being used. The "included side" in ASA is the side between the angles being used.

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Show that 2/4-x = 10/4+x<br><br> is equivalent to 12x = 32 for all values of x not equal to 4 or -4
Anika [276]

Answer:

See proof below

Step-by-step explanation:

Given the expression 2/4-x = 10/4+x

Cross multiply

10(4-x) = 2(4+x)

10(4) - 10x = 2(4)+ 2x

40 - 10x = 8 + 2x

-10x - 2x = 8 - 40

-12x = -32

Multiply both sides by -1

-1(-12x) = -1(-32)

12x = 32

This shows the required expression

6 0
3 years ago
Which matrix multiplication is possible?
Gwar [14]

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Thus, only last case is possible.

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3 years ago
What is your current debt ratio as a percentage to the nearest hundredth?
olasank [31]

Answer:

Step-by-step explanation: see attachment below

4 0
4 years ago
3x - [2 +3 (2-x) = S-(3-X)
Korolek [52]
What is the value of x?
8 0
2 years ago
The length of a rectangle is 8 inches longer than the width. If the area is 295 square inches, find the
sladkih [1.3K]

Answer:

L=21.6in and w=13.6

Step-by-step explanation:

If the length is 8 inches longer than its width, we can write the width as "w" and the length as the width w+ 8

Area is (width)(Length) = (width)(width+8)

W

----------

| |

| |

| | L = w+8

| |

| |

-----------

A = (w+8)(w)

A = w2 + 8w = 295.

(Problem states that area is 295 sq in)

Need to solve this quadratic equation

w2 +8y - 295 = 0

Factor:

(w - 13.64) (w + 21.64) = 0

So

w - 13.64 = 0. or. w + 21.64= 0

Solve these and get

w = 13.64. or. w = -21.64

Only one that makes sense in real life is the poitive one.

So the dimensions are

Width = 13.64 inches

Length = 21.64 inches

7 0
3 years ago
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