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3 years ago

If you earn $600 per month at your part-time job, and save 75% of that, how much

Mathematics

2 answers:

Tpy6a [65]3 years ago

3 0

Answer: 5400 dollars

Step-by-step explanation: 600x.75 then 450x12

hichkok12 [17]3 years ago

3 0

Answer:

Saving after 1 year will be $5400.

Explanation:

Given:

Earning in one month = $600

Saving in one month = 75 % of earning

To Find:

Need to calculate saving for the year.=?

Solution:

Lets first calculate saving for 1 month

saving in one month = 75 % of earning

=> Saving in one month = 75% of 600

=> $\frac{75}{100}\times600$ =$450

So saving for 12 months = 12 x saving in one month = 12 x 450 = 5400

Saving in a year = saving in 12 months = $5400

Hence saving after 1 year will be $5400.

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Find the monthly payment for the loan. Finance $500,000 for an apartment complex with a 12.3% 10-year loan.

Marina86 [1]

Using it's formula, it is found that the monthly payments for the loan of the apartment is of $7,260.50.

<h3>What is the monthly payment formula?</h3>

It is given by:

$A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}$

In which:

P is the initial amount.

r is the interest rate.

n is the number of payments.

In this problem, the parameters are given as follows:

P = 500000, r = 0.123, n = 12 x 10 = 120.

Hence:

r/12 = 0.123/12 = 0.01025.

Then, the monthly payments will be of:

$A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}$

$A = 500000\frac{0.01025(1+0.01025)^{120}}{(1+0.01025)^{120} - 1}$

A = 7260.50.

More can be learned about the monthly payment formula at brainly.com/question/26267630

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2 years ago

the expression 8+2t can be used to find the total cost of admission and t amusement rides at a country fair. what statement is t

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3 years ago

What is the equation of a line that passes through the point (8, 1) and is perpendicular to the line whose equation is y=−2/3x+5

swat32

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$l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}$

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Answer: $\boxed{y=\dfrac{3}{2}x-11}$

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3 years ago

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3 years ago

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Ede4ka [16]

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1 year ago