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astra-53 [7]
3 years ago
12

In 3/4 pound of a spice mix there is 5/6 cup of cinnamon how much is it if it is a spice mix contain per pound?

Mathematics
1 answer:
nordsb [41]3 years ago
5 0

There are 10/9 cups of cinnamon in 1 pound of spice mix

and if you wanna convert the improper fraction to a mixed number it will be 11/9

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Sketch each line and find the slop and Y-intercept
Anon25 [30]
Lol where the problem
6 0
4 years ago
Researchers have claimed that the average number of headaches per student during a semester of Statistics is 11. In a sample of
SSSSS [86.1K]

Answer:

A) H0: μ = 11 vs. Ha: μ > 11

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

Therefore, for the case above;

The null hypothesis is that the average number of headaches per student during a semester of Statistics is 11.

H0: μ = 11

The alternative hypothesis is that the average number of headaches per student during a semester of Statistics is greater than 11.

Ha: μ > 11

4 0
4 years ago
The lengths of a rectangle have been measured to the nearest tenth of a centimetre they are 87.3cm and 51.8cm what is the upper
vagabundo [1.1K]

Answer: Area (upper bound) = 4527.7056 cm²

               Perimeter (lower bound) = 278 cm

<u>Step-by-step explanation:</u>

The length and width of the rectangle have been ROUNDED to the nearest tenth. Let's calculate what their actual measurements could be:

LENGTH: rounded to 87.3,  actual is between 87.25 and 87.34

<em>87.25 is the lowest number it could be that would round it UP to 87.3</em>

<em>87.34 is the highest number it could be that would round DOWN to 87.3</em>

WIDTH: rounded to 51.8, actual is between 51.75 and 51.84

<em>51.75 is the lowest number it could be that would round it UP to 51.8</em>

<em>51.84 is the highest number it could be that would round DOWN to 51.8</em>

To find the Area of the upper bound, multiply the highest possible length and the highest possible width:

A = 87.34 × 51.84 = 4527.7056

To find the Perimeter of the lower bound, calculate the perimeter using the lowest possible length and the lowest possible width:

P = 2(87.25 + 51.75) = 278

8 0
4 years ago
Read 2 more answers
The domain of the following relation R {(6, −2), (1, 2), (−3, −4), (−3, 2)} is (1 point)
Karolina [17]

Answer:

Domain: { -3,1,6}

Step-by-step explanation:

The domain is the input values

Domain: { 6,1,-3,-3}

We usually put them in numerical order and we do not list the same value twice

Domain: { -3,1,6}

4 0
3 years ago
"We might think that a ball that is dropped from a height of 15 feet and rebounds to a height 7/8 of its previous height at each
tatyana61 [14]

Answer:

Total Time = 4.51 s

Step-by-step explanation:

Solution:

- It firstly asks you to prove that that statement is true. To prove it, we will need a little bit of kinematics:

                             y = v_o*t + 0.5*a*t^2

Where,   v_o : Initial velocity = 0 ... dropped

              a: Acceleration due to gravity = 32 ft / s^2

              y = h ( Initial height )

                             h = 0 + 0.5*32*t^2

                             t^2 = 2*h / 32

                             t = 0.25*√h   ...... Proven

- We know that ball rebounds back to 7/8 of its previous height h. So we will calculate times for each bounce:

1st : 0.25*\sqrt{15}\\\\2nd: 0.25*\sqrt{15} + 0.25*\sqrt{15*\frac{7}{8} } + 0.25*\sqrt{15*\frac{7}{8} } = 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} }\\\\3rd: 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} } + 2*0.25*\sqrt{15*(\frac{7}{8} })^2\\\\= 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} } + 0.5*\sqrt{15*(\frac{7}{8} })^2\\\\4th: 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} } + 0.5*\sqrt{15*(\frac{7}{8} })^2 + 2*0.25*\sqrt{15*(\frac{7}{8} })^3 \\\\

= 0.25*\sqrt{15} + 0.5*\sqrt{15*\frac{7}{8} } + 0.5*\sqrt{15*(\frac{7}{8} })^2 + 0.5*\sqrt{15*(\frac{7}{8} })^3

- How long it has been bouncing at nth bounce, we will look at the pattern between 1st, 2nd and 3rd and 4th bounce times calculated above. We see it follows a geometric series with formula:

  Total Time ( nth bounce ) = Sum to nth ( \frac{1}{2}*\sqrt{15*(\frac{7}{8})^(^i^-^1^) }  - \frac{1}{4}*\sqrt{15})

- The formula for sum to infinity for geometric progression is:

                                   S∞ = a / 1 - r

Where, a = 15 , r = ( 7 / 8 )

                                   S∞ = 15 / 1 - (7/8) = 15 / (1/8)

                                   S∞ = 120

- Then we have:

                                  Total Time = 0.5*√S∞ - 0.25*√15

                                  Total Time = 0.5*√120 - 0.25*√15

                                  Total Time = 4.51 s

5 0
3 years ago
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