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3 years ago

Can the common ratio of geometric sequence be equal to 0?

Mathematics

1 answer:

NeTakaya3 years ago

8 0

Answer:

No it cant

Step-by-step explanation:

it cant

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One line passes through the points \blueD{(-3,-1)}(−3,−1)start color #11accd, (, minus, 3, comma, minus, 1, ), end color #11accd

mart [117]

Answer:

The lines are perpendicular

Step-by-step explanation:

we know that

If two lines are parallel, then their slopes are the same

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

Remember that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

Find the slope of the first line

we have the points

(-3,-1) and (1,-9)

substitute in the formula

$m_1=\frac{-9+1}{1+3}$

$m_1=\frac{-8}{4}$

$m_1=-2$

Find the slope of the second line

we have the points

(1,4) and (5,6)

substitute in the formula

$m_2=\frac{6-4}{5-1}$

$m_2=\frac{2}{4}$

Simplify

$m_2=\frac{1}{2}$

Compare the slopes

$m_1=-2$

$m_2=\frac{1}{2}$

Find out the product

$m_1*m_2=(-2)(\frac{1}{2})=-1$

therefore

The lines are perpendicular

8 0

3 years ago

Read 2 more answers

Solve the inequality x^2-4x-7<0

ANEK [815]

Answer:

Inequality Form:

2 − √ 11 < x < 2 + √ 11

Interval Notation:

( 2 − √ 11 , 2 + √ 11 )

Step-by-step explanation:

Solve the inequality for x by finding a , b , and c of the quadratic then applying the quadratic formula.

8 0

3 years ago

Easy points :) 2*2*2+2-1

kipiarov [429]

Answer:

Step-by-step explanation:

2*2=4*2=8+2=10-1=9

7 0

3 years ago

NEED HELP URGENT PLEASE IMAGE IN DESCRIPTION NO TROLL PLEASE BE NICE!!!

LiRa [457]

Answer:

23-5= 18

Step-by-step explanation:

4 0

3 years ago

need help. solve for y. try factoring first if not possible or difficult use quadratic formula. y²-6y+6=0

lbvjy [14]

$y^2-6y+6=0\\ \\a=1 , \ b=-6, \ c=6 \\ \\\Delta =b^2-4ac = (-6)^2 -4\cdot1\cdot6 = 36-24=12\\ \\\sqrt{\Delta }= \sqrt{12}=\sqrt{4\cdot 3}=2\sqrt{3} \\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{6-2\sqrt{3}}{2 }=\frac{2( 3- \sqrt{3})}{2}= 3- \sqrt{3}$

$x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{6+2\sqrt{3}}{2 }=\frac{2( 3+ \sqrt{3})}{2}= 3+ \sqrt{3}$

3 0

3 years ago

Read 2 more answers