Answer:
3m / 7 = 7n / 3
49n = 9m
9m / 49n = 1
m / n = 49 / 9
Step-by-step explanation:
There are a total of 20 snacks in each bag. We consider the probability of picking a bag of peanuts with reduced sodium and then a granola bar with reduced sodium, then multiply by 2 (because we could pick them in the other order).
There is a 5/20 chance of picking a sodium-reduced bag of peanuts first, and a 2/20 chance of picking a sodium-reduced granola bar next. Thus, the chance of picking them together in that order is 5/20*2/20=10/400, or 1/40. Because we could pick the snacks in either order, we multiply by two, for a result of a 1/20 probability.
What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}
Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70}
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median.
The value in the 8th slot is 54, so this is the median
Divide the sorted data set into two lists. I'll call them L and U
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).
Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value.
Therefore, Q3 = 62
Answer: 62</span>
- 3 + u = - 20
u = - 20 + 3
u = -17
hope this helps!.
