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notka56 [123]
3 years ago
12

Which graph represents this exponential function? f(x)=3(2)^x-4

Mathematics
1 answer:
Rasek [7]3 years ago
4 0

Answer:

A

Step-by-step explanation:

look up desmos graphing calculator and it graphs all of your equations for you. I used it all through high school.

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Solve the system of linear equations. separate the x- and y- values with a coma. -5x+6y=33 -18x+4y=-22
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Classify the following triangle. check all that apply
Vsevolod [243]

Answer is acute and scalene

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Can someone please help with this trig question?
atroni [7]
First we must understand how to write a logarithmic function:

log_{b}a=x

In the equation above, b is the base, x is the exponent, and a is the answer. These same variables can be rearranged to be expressed as an exponential equation as followed:

b^x=a

Next, we need to understand basic logarithm rules.

1. When a value is raised to a power, we can move the exponent to the front of the logarithm. Example:

log(a^2) = 2log(a)

2. When two variables are multiplied together, we can add the logarithms of the individual variables together. Example:

log(ab) = log(a) + log(b)

3. When a variable is divided by another variable, we can subtract the logarithms of the individual variables. Example:

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Now we can use these rules to solve the problem.

log(r)=log( \sqrt[3]{ \frac{A^2B}{C} } )

We can rewrite the cube root as:

log(r) = log( (\frac{A^2B}{C})^ \frac{1}{3} )

Now we can move  the one-third to the front:

log(r) =  \frac{1}{3} log( \frac{A^2B}{C} )

Now we can split up the logarithm:

log(r) =  \frac{1}{3} (log(A^2)+log(B)-log(C))

Finally, we can move the exponent to the front of the log of A:

log(r) = \frac{1}{3} (2log(A)+log(B)-log(C))

Distribute the one-third to get the answer:

log(r) = \frac{2}{3} log(A) +  \frac{1}{3} log(B) -  \frac{1}{3} log(C)

The answer is (4).


3 0
3 years ago
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