The difference in distance between Aero plane A and B is; 34.67 km
<h3>How to calculate bearing?</h3>
To get the bearing;
∠H = (115 - 90) + (270 - 203)
∠H = 92°
Then, we will use cosine rule to get the distance between both Planes A and B.
d_ab = √(18² + 29² - 2(18 * 29) * cos 92)
d_ab = √(324 + 841 + 36.435)
d_ab = 34.67 km
Read more about bearing at; brainly.com/question/22518031
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Answer: 
<u>Simplify both sides of the equation</u>
<u>Subtract 5n from both sides</u>
<u>Subtract 15 from both sides</u>
Answer:
m<T = , m<M = and m<Z =
Step-by-step explanation:
From the given ∆TMZ, let the measure angle T be represented by T.
So that,
m<M = 2T + 6°
m<Z = 5T - 50°
Sum of angles in a triangle =
T + (2T + 6°) + (5T - 50°) =
8T - =
8T = +
=
T =
=
Therefore,
i. m<T =
ii. m<M = 2T + 6°
= 2 x + 6°
=
m<M =
iii. m<Z = 5T - 50°
= 5 x - 50°
= - 50°
=
m<Z =
Huh? this is very confusing 12
