Answer:
k=188.46 N/m
Explanation:
Given that
m= 30 gm
Additional mass = ΔM
Lets take spring coefficient = k
at the equilibrium position
F= k Δl =( m + ΔM)g
Δl = change in the spring length
k Δl = ( m + ΔM)g
Δl = m g /k + g/k ΔM ---------------1
We know that equation of line given as
y = c + S x -----------------2
By compare equation 2 and 1
slope = s
S= g/k
Given that slope S= 0.052 m/kg
S =g/ k= 0.052
g=9.8 m/s²
9.8 = 0.052 k
k=188.46 N/m
So the spring constant is 188.46 N/m
Answer:
3. you need to ask your available lab instructors what to do.
4. You immediately have to drop down your cloth and roll it to extinguish the fire or move to the emergency shower if available
5. You have too keep calm and report to the lab instructor but do no shout.
6. Move immediately to the eye rinse basin if available and wash your eyes gently and thoroughly
Answer:
Explanation:
(1) I= 1.5W/240V =6.25mA
(2) Energy= (1.5J/s)×(2×60×60 s)=10.8 KJ
Answer:
A
Explanation:
because it is accelerating and as the vehicle accelerates the speed increas
They attract each other with force
F=q1*q2/(4πεr^2), where
q1=2.4 µC, q2=4.2 µC,
r=4.9·10-2 m, ε=8.854·10^(-12) SI units.
♦ F=2.4·10-6 * 4.2·10-6 /(4*pi* 8.854·10^(-12) *0.049^2)=
=37.73 N;