Answer:
The temperature after half an hour is ![19.3002^{\circ}](https://tex.z-dn.net/?f=19.3002%5E%7B%5Ccirc%7D)
Solution:
As per the question;
Metabolic rate of the person is 3.0105 J/h
Temperature, T = ![19.30^{\circ}](https://tex.z-dn.net/?f=19.30%5E%7B%5Ccirc%7D)
Mass of the water, ![m_{w} = 1.2103 kg](https://tex.z-dn.net/?f=m_%7Bw%7D%20%3D%201.2103%20kg)
Time duration, t = 0.5 h = 30 min = 180 s
Now,
Heat, ![Q = ms\Delta t](https://tex.z-dn.net/?f=Q%20%3D%20ms%5CDelta%20t)
Thus heat transfer in half an hour:
![Q = 3.0105\times 0.5 = 1.505 J](https://tex.z-dn.net/?f=Q%20%3D%203.0105%5Ctimes%200.5%20%3D%201.505%20J)
Now, the temperature of water after half an hour, T' is given by:
![Q = m_{w}s\Delta T = ms(T' - T)](https://tex.z-dn.net/?f=Q%20%3D%20m_%7Bw%7Ds%5CDelta%20T%20%3D%20ms%28T%27%20-%20T%29)
where
s = 4186 J
![1.505 = 1.21103\times 4186\times (T' - 19.30^{\circ})](https://tex.z-dn.net/?f=1.505%20%3D%201.21103%5Ctimes%204186%5Ctimes%20%28T%27%20-%2019.30%5E%7B%5Ccirc%7D%29)
![T' = 19.3002 ^{\circ}](https://tex.z-dn.net/?f=T%27%20%3D%2019.3002%20%5E%7B%5Ccirc%7D)
The answer is actually True, I just took the test and it was correct.
Answer:
7.48 x 10⁵ m
Explanation:
g = 7.86 N/kg
M = 5.97 x 10²⁴ kg, R = 6.37 x 10⁶ m.
Find height h
g = GM/(R + h)²
(R + h)² = GM/g = 6.67 x 10⁺¹¹ x 5.97 x 10²⁴ /7.86 = 5.066 x 10¹³
R + h = 7.12 x 10⁶ m
so
h = 7.12 x 10⁶ - 6.37 x 10⁶ = 7.48 x 10⁵ m
The first, fourth and sixth options. A person walks up a flight of stairs, wind lifts a balloon into the air, and a weightlifter holds a barbell straight overhead.