All categories

3 years ago

What should you do if...

Physics

1 answer:

Hunter-Best [27]3 years ago

6 0

Answer:

3. you need to ask your available lab instructors what to do.

4. You immediately have to drop down your cloth and roll it to extinguish the fire or move to the emergency shower if available

5. You have too keep calm and report to the lab instructor but do no shout.

6. Move immediately to the eye rinse basin if available and wash your eyes gently and thoroughly

You might be interested in

Two 1 MHz radio antennas emitting in-phase are separated by600

algol [13]

Answer:

1 km

Explanation:

$d_0$ = Gap between antennas = 600 m

$\nu$ = Frequency = 1 MHz

$z_1$ = Distance to receiver = 2 km

c = Speed of light = $3\times 10^8\ m/s$

Wavelength is given by

$\lambda=\dfrac{c}{\nu}\\\Rightarrow \lambda=\dfrac{3\times 10^8}{1\times 10^6}\\\Rightarrow \lambda=300\ m$

Distance to be moved is given by

$D=\dfrac{z_1\lambda_0}{d_0}\\\Rightarrow D=\dfrac{2\times 300}{600}\\\Rightarrow D=1\ km$

The distance to be moved is 1 km north.

6 0

3 years ago

Given a particle that has the velocity v(t) = 3 cos(mt) = 3 cos (0.5t) meters, a. Find the acceleration at 3 seconds. b. Find th

DiKsa [7]

Answer:

a. $\rm -1.49\ m/s^2.$

b. $\rm 50.49\ m.$

Explanation:

<u>Given:</u>

Velocity of the particle, v(t) = 3 cos(mt) = 3 cos (0.5t) .

The acceleration of the particle at a time is defined as the rate of change of velocity of the particle at that time.

$\rm a = \dfrac{dv}{dt}\\=\dfrac{d}{dt}(3\cos(0.5\ t ))\\=3(-0.5\sin(0.5\ t.))\\=-1.5\sin(0.5\ t).$

At time t = 3 seconds,

$\rm a=-1.5\sin(0.5\times 3)=-1.49\ m/s^2.$

<u>Note</u>:<em> The arguments of the sine is calculated in unit of radian and not in degree.</em>

The velocity of the particle at some is defined as the rate of change of the position of the particle.

$\rm v = \dfrac{dr}{dt}.\\\therefore dr = vdt\Rightarrow \int dr=\int v\ dt.$

For the time interval of 2 seconds,

$\rm \int\limits^2_0 dr=\int\limits^2_0 v\ dt\\r(t=2)-r(t=0)=\int\limits^2_0 3\cos(0.5\ t)\ dt$

The term of the left is the displacement of the particle in time interval of 2 seconds, therefore,

$\Delta r=3\ \left (\dfrac{\sin(0.5\ t)}{0.05} \right )\limits^2_0\\=3\ \left (\dfrac{\sin(0.5\times 2)-sin(0.5\times 0)}{0.05} \right )\\=3\ \left (\dfrac{\sin(1.0)}{0.05} \right )\\=50.49\ m.$

It is the displacement of the particle in 2 seconds.

7 0

4 years ago

Help me please i need this to passsss

mamaluj [8]

Answer: D

Explanation: : ⊇

6 0

3 years ago

Which involves more work in the scientific sense: moving the boxes and the furniture down from the second floor or up to the fif

Advocard [28]

Answer:

moving the boxes and the furniture up to the fifth floor.

Explanation:

The work done when moving an object up or down is equal to its change of gravitational potential energy:

$W=mg \Delta h$

where

m is the mass of the object

g is the gravitational acceleration

$\Delta h$ is the change in height of the object

We have two opposite situations:

1) when an object is moved upward, $\Delta h$ is positive, so the work done W is positive as well: this means that we need to do work in order to move the object, because we have to "win" the effect of gravity, which pulls the object downward

2) when an object is moved downward, $\Delta h$ is negative, so the work done W is negative as well: this means that we do not need to do work on the object, because it is already done by gravity, which pulls the object downward.

Therefore, more work is done when we are moving the boxes and the furniture up to the fifth floor.

8 0

3 years ago

What process do bats use to navigate?

Kazeer [188]

Answer:

B. Echolocation

Explanation:

The process bats use to navigate is echolocation.

4 0

3 years ago

Read 2 more answers