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Radda [10]
2 years ago
8

An electrical appliances

Physics
1 answer:
sladkih [1.3K]2 years ago
6 0

Answer:

Explanation:

(1) I= 1.5W/240V =6.25mA

(2) Energy= (1.5J/s)×(2×60×60 s)=10.8 KJ

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An artist wants to create a metal sculpture using a mold so that his artwork can be readily mass produced. He wants his sculptur
lukranit [14]

Answer:NO

Explanation:

No the mold should not be of the same size as that of sculpture because the material from which molds is made may shrink or expand depending upon its properties .

For example grey cast iron shrinks on cooling.

We need to make mold bigger in general so that if there is a need of finishing it can be done easily without altering the size of sculpture.

5 0
3 years ago
Which of the following illustrates 2 resistors in a parallel circuit?
marta [7]
A illustrates 2 resistors in a parallel circuit.
3 0
3 years ago
Read 2 more answers
A gardener uses a 60-N wheelbarrow to transport two bags of fertilizer weighing W = 252-N. Determine the maximum allowable horiz
Butoxors [25]

Explanation:

Let us assume that the maximum allowable horizontal distance be represented by "d".  

Therefore, torque equation about A will be as follows.

   60 \times 0.15 + 252 \times 0.15 \times 2 + 252 \times d = 2 \times 75 \times (0.7 + 0.15 + 0.15)

      d = \frac{[2 \times 75 \times (0.7+0.15+0.15) - 60 \times 0.15 - 252 \times 0.15 \times 2]}{252}

       d = 0.409 m

Thus, we can conclude that the maximum allowable horizontal distance from the axle A of the wheelbarrow to the center of gravity of the second bag if she can hold only 75 N with each arm is 0.409 m.

6 0
3 years ago
A particle with a charge of 3.00 elementary charges moves through a potential difference of 4.50 volts. What is the change in el
GuDViN [60]

Answer:

7.2\cdot 10^{-19} J

Explanation:

The change in electrical potential energy of a charged particle moving through a potential difference is given by

\Delta U = q \Delta V

where

q is the magnitude of the charge of the particle

\Delta V is the potential difference

In this problem:

- the charge of the particle is 3.00 elementary charges, so

q=3e=3\cdot 1.6\cdot 10^{-19} J=4.8\cdot 10^{-19}J

- the potential difference is

\Delta V=4.50 V

So, the change in electrical potential energy is

\Delta U=(1.6\cdot 10^{-19}C)(4.50 V)=7.2\cdot 10^{-19} J

7 0
3 years ago
2. Four metal mugs with lids each contain the same volume of hot water at the same temperature. The mugs are made from the same
olga_2 [115]

Answer:

D. the mug painted dull black

4 0
1 year ago
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