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Radda [10]
2 years ago
8

An electrical appliances

Physics
1 answer:
sladkih [1.3K]2 years ago
6 0

Answer:

Explanation:

(1) I= 1.5W/240V =6.25mA

(2) Energy= (1.5J/s)×(2×60×60 s)=10.8 KJ

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Enter the expression 2cos2(θ)−1, where θ is the lowercase Greek letter theta.
vlabodo [156]
GAVNSTVVHUYCZ swffggff
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3 years ago
You are an evolutionary biologist studying a population of bats in the rain forest in Brazil. Most of the population possesses m
Oxana [17]

Answer:

Option (B)

Explanation:

In the stabilizing natural selection, the extreme traits from both the ends are eliminated by natural selection and natural selection favors the intermediate trait. So over time individuals having the intermediate traits are selected over the individuals having extreme traits.

So here the population of the bat which possesses moderate wing length is selected over the individual with extreme traits like individuals with short wings and long wings. As a result, the population of moderate length wing bats increased.

Therefore the correct answer is (B)- stabilizing natural selection.

3 0
3 years ago
Raju learned about green plants, he found out that green plants can make their own food in the presence of sunlight a) Name the
baherus [9]

Answer:

Photosynthesis is the pocess by which green plants make their own food.

b. sunlight, glucose, water, altra-violet ray as catalyst

7 0
3 years ago
an airplane travels 2100 km at a speed of 1000 km/h for the next 1300 km. whatis the average speed for this plane trip?
Vanyuwa [196]

wouldn't it be 1000 km/h considering the plane was travelling the same speed for over half the trip?

4 0
3 years ago
Consider an oblique shock wave with a wave angle of 35 o . Upstream of the wave, the static pressure and temperature are 2,000 l
ziro4ka [17]

Answer:

The pressure is 6570  lbf/ft²

The temperature is 766 ⁰R

The velocity is 2746.7 ft/s

deflection angle behind the wave is 17.56⁰

Explanation:

Speed of air at initial condition:

a_1 = \sqrt{\gamma RT } =  \sqrt{1.4* 1716*520 } = 1117.70 \ ft/s

γ is the ratio of specific heat, R is the universal gas constant, and T is the initial temperature.

initial mach number

M_1 = \frac{v_1}{a_1} = \frac{3355}{1117.7}  = 3

then, M_n = M_1sin \beta = 3sin(35) = 1.721

based on the values obtained, read off the following from table;

P₂/P₁ = 3.285

T₂/T₁ = 1.473

Mₙ₂ = 0.6355

Thus;

P₂ = 3.285P₁ = 3.285(2000) = 6570  lbf/ft²

T₂ = 1.473T₁ = 1.473(520⁰R) = 766 ⁰R

Again; to determine the velocity and deflection angle, first we calculate the mach number.

M_t_1 = M_1cos \beta = 3 cos(35) = 2.458

w_2 = a_1M_t_1 = 2.458(1117.70) = 2746.7 \ ft/s

a_2 = \sqrt{\gamma RT_2} = \sqrt{1.4*1718*766} = 1357.34 \ ft/s

v_2 = a_2M_n_2 = 1357.34(0.6355) = 862.59 \ ft/s

Tan(\beta -\theta) = \frac{v_2}{w_2} = \frac{862.59}{2746.7}  \\\\Tan(\beta -\theta) = 0.314\\\\\beta -\theta= 17.44\\\\\theta = \beta - 17.44 = 17.56^o

6 0
3 years ago
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