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2 years ago

Here is a list of numbers: 2, 13, 13, 6, 10,4 16,14,20 State the median.

Mathematics

2 answers:

Travka [436]2 years ago

5 0

Answer:

Median = 13

Step-by-step explanation:

Arranging it in ascending order:

=> 2,4,6,10,13,13,14,16,20

Median is the middlemost no.

So,

=> Median = 13

liraira [26]2 years ago

5 0

Median is = 3
Hope it’s right x

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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

J(2;5); K(1;1)

=> JK = $\sqrt{(1-2)^{2} + (1-5)^{2} } = \sqrt{(-1)^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

J(2;5); L(5;2)

=> JL = $\sqrt{(5-2)^{2} + (2-5)^{2} } = \sqrt{3^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

K(1;1); L(5;2)

=> KL = $\sqrt{(5-1)^{2} + (2-1)^{2} } = \sqrt{4^{2}+1^{2} } = \sqrt{1+16}=\sqrt{17}$

In the triangle QNP, the sides can be calculate as following:

Q(-4;4); N(-3;0)

=> QN = $\sqrt{[-3-(-4)]^{2} + (0-4)^{2} } = \sqrt{1^{2}+(-4)^{2} } = \sqrt{1+16}=\sqrt{17}$

Q (-4;4); P(-7;1)

=> QP = $\sqrt{[-7-(-4)]^{2} + (1-4)^{2} } = \sqrt{(-3)^{2}+(-3)^{2} } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}$

N(-3;0); P(-7;1)

=> NP = $\sqrt{[-7-(-3)]^{2} + (1-0)^{2} } = \sqrt{(-4)^{2}+1^{2} } = \sqrt{16+1}=\sqrt{17}$

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0

2 years ago

Read 2 more answers

Points (3,2) and (-5,6) are endpoints of the diameter of a circle.

vichka [17]

Answer:

A.8 B.(-1,4) C.(1,4)

Step-by-step explanation:

First, know that (3,2)=(x1,y1) and (-5,6)=(x2,y2)

A. The diameter is 8, given the diference between x1 and x2: 3-(-5)=8

B. The center point is given by (x1+x2)/2 and (y1+y2)/2

(x1+x2)/2 and (y1+y2)/2 = (3-5)/2 and (2+6)/2 = (-1,4)

C. The symmetric point of C about the x-axis is (1,4)

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2 years ago

What is the quadratic function that is created with roots at 2 and 4 and a vertex at (3, 1)?

Arada [10]

Hello,

y=k*(x-2)(x-4)
and is passing throught (3,1)
==>1=k*(3-2)(3-4)==>k=-1

y=-(x-2)(x-4) is an answer

4 0

2 years ago

What type of number is -2i?

Iteru [2.4K]

Answer:

It is an imaginary number.

Step-by-step explanation:

In this example, the real number is -2 is being multiplied by the imaginary unit, i, which i can be also expressed as (√-1).

7 0

2 years ago

4y-8-2y+5=0 help please

tia_tia [17]

4y - 8 - 2y + 5 = 0
2y - 3 = 0
2y = 3
y = 3/2

4 0

2 years ago