Answer:
Answer for the question:
The Rockwell hardness of a metal is determined by impressing a hardened point into the surface of the metal and then measuring the depth of penetration of the point. Suppose the Rockwell hardness of a particular alloy is normally distributed with mean 69 and standard deviation 2.7.
a. If a specimen is acceptable only if its hardness is between 67 and 75, what is the probability that a randomly chosen specimen has an acceptable hardness?
b. If the acceptable range of hardness is (69-C, 69+C), for what value of C would 95% of all specimens have acceptable hardness?
c. If the acceptable range is as in part (a) and the hardness of each of ten randomly selected specimens is independently determined, what is the expected number of acceptable specimens among the ten?
d. What is the probability that at most eight of ten independently selected specimens have a hardness of less than 72.84(HINT Y=number among the ten specimens with hardness less than72.84 is a binomial variable; what is p?)
is given in the attachment.
Step-by-step explanation:
The given equations are:
1) 2y = -x + 9
⇒ x = 9-2y
2) 3x - 6y = -15
⇒3x = 6y - 15
x = 2y - 5
Equating the values of x, we get:
9 - 2y = 2y - 5
9 + 5 = 4y
14 = 4y
y = 3.5
Using this value of y in equation 1 we get:
x = 9 - 2(3.5) = 2
So, the solution set is (2, 3.5)
I think that is 248 min in one day because 24/5 is 4.8. 4hours and 8 min. 4 times 60 is 240. 240 plus 8 is 248 this is what I think.
The line should go from (0,0) to (7,3.5)
The equation is Y = X(0.5)
7cm each. reason: the rod of 21cm lenght will be cut into 3pieces of 7cm each, while that of 14cm will be cut into 2 pieces of 7cm each. Therefore, there 5 pieces of rods of 7cm each. Thanks.
