Let's get into some looping. Sometimes it is nice to generate your own data. Now let's take our first stab at it.
1 answer:
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Answer:
Explanation:
Considering the number are stored using binary notations.
If there are total 86 bits and 1 bit is used as sign bit. Then in total one can have bit combinations since a bit can be either stored as 0 or as 1.
Therefore, the largest number that can be stored will be .
To understand it in better way let's scale down the problem to 3 bits representation. The largest number that can be stored using 3 bits is 111 which in decimal form is 7 and is equal to .
Answer:
Given code output is "786".
Explanation:
Code:
list1 = [ 'cyber', 786 , 2.23, 'square', 70.2 ]#defining a list list1 that holds value in parameter
print (list1[1] )#use a print method that prints list index value
In the given code a list "list1" is declared that holds value in it and in the next step a print method is declared that prints the first index value of the list.
