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Sedaia [141]
4 years ago
5

Urgent math help needed will mark brainliest

Mathematics
1 answer:
iren [92.7K]4 years ago
3 0

Remark

Many calculators have a key that will do this in one step. Mine is one of them. So let's start with the answer and then we'll do it the long way.

9C3 = 84. You put it into your calculator as 9   2nF   nCr 3 =

Solution

\dfrac{9!}{(n - 3)!3!} = \dfrac{9*8*7*6!}{6!*3!}=\dfrac{9*8*7}{6}

3*4*7 = 84 which is what you set out to show.


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9th question help ?!
Daniel [21]
Hey there! :)

You have to find the area of all of them and add it together.

Formulas:

Area of a square: l · w
Area of a triangle: (b · h) ÷ 2

Square - 

l = 3
w = 3

3 × 3 = 9

Triangle - 

b = 3
h = 3

(3 × 3) ÷ 2
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The surface area ⇒ 27 cm²



5 0
4 years ago
PLEASE HELPPPPPPPPPPPPPP
mart [117]

Answer:

None of these can be triangles.

Step-by-step explanation:

All triangles’ side lengths must follow this pattern - the two shortest sides must be GREATER than the longest when added together. 6 + 4 < 10, so this isn’t a triangle. 3 + 8 = 11, so this isn’t a triangle. 8.4 + 7.7 < 16.6, so this isn’t a triangle. Lastly, 4 + 3 < 16, so this isn’t a triangle. Hope this is accurate & helpful! Best of luck.

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=-9.1%5C%20%20%5Ctextless%20%5C%20d-6.3" id="TexFormula1" title="-9.1\ \textless \ d-6.3" alt=
SSSSS [86.1K]
-9.1 < d - 6.3
add 6.3 to both sides
-2.8 < d or d > -2.8
6 0
3 years ago
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