Answer:
D.) $12n + $8u = 112 ;u = 4 + n
Step-by-step explanation:
Given that :
Cost per new books (n) = $12
Cost per used book (u) = $8
Total revenue earned = $112
store sold 4 more used books than new books
Hence,
Total revenue should be :
Revenue from new books + Revenue from used book = total revenue
Revenue from new books = $12 * n = $12n
Revenue from used books = $8 * n = $8n
$12n + $8u = 112
Number of books sold :
Number of used books sold = 4 + number of new books sold
u = 4 + n
Finding the Bearing<span> of a </span>Ship<span>
Example : A </span>ship<span> leaves the port of Miami with a </span>bearing<span> of S80◦E and a </span>speed<span> of. 15 knots. After 1 hour, the </span>ship<span> turns 90◦ toward the south.</span>
Answer:
0.375
Step-by-step explanation:
= 3/8
= 3 ÷ 8
= 0.375
The sum of the given series can be found by simplification of the number
of terms in the series.
- A is approximately <u>2020.022</u>
Reasons:
The given sequence is presented as follows;
A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021
Therefore;
The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;
Therefore, for the last term we have;
2 × 2043231 = n² + 3·n + 2
Which gives;
n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0
Which gives, the number of terms, n = 2020
![\displaystyle \frac{A}{2} = \mathbf{ 1011 \cdot \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460} \right)}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BA%7D%7B2%7D%20%20%3D%20%5Cmathbf%7B%201011%20%5Ccdot%20%20%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%20%2B%5Cfrac%7B1%7D%7B6%7D%20%2B%20%5Cfrac%7B1%7D%7B12%7D%2B...%2B%5Cfrac%7B1%7D%7B4086460%7D%20%20%5Cright%29%7D)
![\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2} +\frac{1}{2} - \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022} \right)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BA%7D%7B2%7D%20%20%3D%201011%20%5Ccdot%20%20%5Cleft%281%20-%20%5Cfrac%7B1%7D%7B2%7D%20%2B%5Cfrac%7B1%7D%7B2%7D%20-%20%20%5Cfrac%7B1%7D%7B3%7D%20%2B%20%5Cfrac%7B1%7D%7B3%7D-%20%5Cfrac%7B1%7D%7B4%7D%20%2B...%2B%5Cfrac%7B1%7D%7B2021%7D-%5Cfrac%7B1%7D%7B2022%7D%20%20%5Cright%29)
Which gives;
![\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2022} \right)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7BA%7D%7B2%7D%20%20%3D%201011%20%5Ccdot%20%20%5Cleft%281%20-%20%5Cfrac%7B1%7D%7B2022%7D%20%20%5Cright%29)
![\displaystyle A = 2 \times 1011 \cdot \left(1 - \frac{1}{2022} \right) = \frac{1032231}{511} \approx \mathbf{2020.022}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%20A%20%3D%202%20%5Ctimes%201011%20%5Ccdot%20%20%5Cleft%281%20-%20%5Cfrac%7B1%7D%7B2022%7D%20%20%5Cright%29%20%3D%20%5Cfrac%7B1032231%7D%7B511%7D%20%5Capprox%20%5Cmathbf%7B2020.022%7D)
Learn more about the sum of a series here:
brainly.com/question/190295
Answer:
ah yes mama
Step-by-step explanation: