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ruslelena [56]
3 years ago
5

Total Cost (in dollars)

Mathematics
1 answer:
Crank3 years ago
6 0
This problem has been solved! See the answer Determine Um (mode ), average U, and Urms for a group of ten automobiles clocked by radar at speeds 38,44,48,50,55,55,57,58 and 60mi/h respectively
You might be interested in
It takes Drew 1/10 hour to walk a 1/6 mile park loop. What is Drew's unit rate, in miles per hour?
meriva
1/10 hour = 10 minutes

1/6 mile loop in 10 minutes.
1/6*6/1, 10*6=60
1 Mile every 60 minutes.

By unit rate, do you mean miles per hour? If so:
Drew walks 1 mile per hour.
7 0
4 years ago
If (x+28y)/x=50 then what does (y+28x)/y=
tankabanditka [31]

Answer:

17

Step-by-step explanation:

(x+28y)/x =50

Multiply each side by x

(x+28y)/x *x =50*x

x+28y = 50x

Subtract x

x-x+28y = 50x-x

28y = 49x

Divide by y

28y/y = 49x/y

28 = 49 x/y

Divide by 49

28/49 = x/y

We want to find

(y+28x)/y

Rewriting as

y/y +28 (x/y)

1 + 28(x/y)

Replacing x/y with (28/49)

1 + 28(28/49)

1 +28*28/49

1+784/49

1+16

17


7 0
3 years ago
On the planet of Mercury, 4-year-olds average 3 hours a day unsupervised. Most of the unsupervised children live in rural areas,
erastova [34]

Answer:

a

The distribution of  X is normal

b

P(X  <  1.4) = 0.12654

c

P(X  >  3.5) = 0.36051

Step-by-step explanation:

From the question we are told that

   The population mean is  \mu =  3 \  hours

   The standard deviation is  \sigma  =  1.4 \ hours

Generally given from the question that the amount of time spent alone by the population size is normally distributed then then the distribution of X (i.e the amount of time spent by the sample size (the one Mercurian)) will be normally distributed

  Generally the probability that the child spend less than one hour in a day is mathematically represented as

        P(X  <  1.4) =  P(\frac{X - \mu}{\sigma} < \frac{1.4 - \mu}{\sigma}   )

Here \frac{X - \mu}{\sigma }  =  Z (The\ standardized\ value\ of\  X)

So

      P(X  <  1.4) =  P(Z < \frac{1.4 - 3.0}{1.4}   )

     P(X  <  1.4) =  P(Z < -1.1429  )

From the z-table the value of  

        P(Z < -1.1429  )=0.12654

So     P(X  <  1.4) = 0.12654

Generally the percentage of children that spends over 3.5 hours unsupervised is mathematically represented as

        P(X  >  3.5) =  P(\frac{X - \mu}{\sigma} > \frac{3.5 - \mu}{\sigma}   )

        P(X >  3.5) =  P(Z > \frac{3.5 - 3.0}{1.4}   )

        P(X >  3.5) =  P(Z > 0.3571  )

From the z-table the value of  

        P(Z >0.3571  )=0.36051

So     P(X  >  3.5) = 0.36051

5 0
3 years ago
Find the first four positive values of arccos(0.7). I know how to get the first, but as for the rest, I am lost.
Mandarinka [93]
Now cos⁻¹(0.7) is about 45.6°, that's on the first quadrant.

keep in mind that the inverse cosine function has a range of [0, 180°], so any angles it will spit out, will be on either the I quadrant where cosine is positive or the II quadrant, where cosine is negative.

however, 45.6° has a twin, she's at the IV quadrant, where cosine is also positive, and that'd be 360° - 45.6°, or 314.4°.

now, those are the first two, but we have been only working on the [0, 360°] range.... but we can simply go around the circle many times over up to 720° or 72000000000° if we so wish, so let's go just one more time around the circle to find the other fellows.

360° + 45.6° is a full circle and 45.6° more, that will give us the other angle, also in the first quadrant, but after a full cycle, at 405.6°.

then to find her twin on the IV quadrant, we simply keep on going, and that'd be at 360° + 360° - 45.6°, 674.4°.

and you can keep on going around the circle, but only four are needed this time only.
6 0
3 years ago
Model 2 illustrates a chemical reaction. write the reaction as an equation, using the name or abbreviation of each of the two re
Valentin [98]
The reaction as an equation, using the abbreviation or the name of each two reactants and each of the three products is Adenosine Diphosphate + ATP = Pi.The equation in this question that use the name or the abbreviation is Adenosine Diphosphate + ATP = Pi. The answer in this question is Adenosine Diphosphate + ATP = Pi.
5 0
3 years ago
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