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Zanzabum
3 years ago
15

Are these 2 ratios equivalent ratios?

Mathematics
2 answers:
alexgriva [62]3 years ago
4 0

Answer:

Yes

Step-by-step explanation:

We can prove this by multiplying both the first numerator and the first denominator by six. This leads us to our second ratio. Hope this helps. :)

Eva8 [605]3 years ago
3 0
These ratios are equivalent because 7 and 8 can be multiplied by 6 to get 42 and 48.
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Joe is 20 years old. His sister is half his age less 7. How old is his sister?
MakcuM [25]
The answer is 3. 20/2=10 10-7=3
3 0
3 years ago
A parallelogram has a length of 15cm and a height of 7.5cm . Calculate it’s area (step by step)
poizon [28]

Answer:

Area of parallelogram is equal to 112.5cm^2

Step-by-step explanation:

It is given length pf parallelogram which is equal to base of parallelogram is b=15 cm

Height of parallelogram h = 7.5 cm

We have to find the area of the parallelogram.

Area of parallelogram is equal to multiplication of base and height.

Therefore area of parallelogram is,

A=bh, here b is base and h is height.

So A=15\times 7.5=112.5cm^2

Therefore area of parallelogram is equal to 112.5cm^2

3 0
3 years ago
For a fair coin, suppose you toss the coin 100 times.
Natasha_Volkova [10]

Using the normal distribution, it is found that there is a 0.0005 = 0.05% probability of getting more than 66 heads.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with \mu = np, \sigma = \sqrt{np(1-p)}.

For the binomial distribution, the parameters are given as follows:

n = 100, p = 0.5.

Hence the mean and the standard deviation of the approximation are given as follows:

  • \mu = np = 100(0.5) = 50.
  • \sigma = \sqrt{np(1-p)} = \sqrt{100(0.5)(0.5)} = 5

Using continuity correction, the probability of getting more than 66 heads is P(X > 66 + 0.5) = P(X > 66.5), which is <u>one subtracted by the p-value of Z when X = 66.5</u>.

Z = \frac{X - \mu}{\sigma}

Z = \frac{66.5 - 50}{5}

Z = 3.3

Z = 3.3 has a p-value of 0.9995.

1 - 0.9995 = 0.0005.

0.0005 = 0.05%

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

6 0
2 years ago
Sebastian is going to invest in an account paying an interest rate of 1.5%
densk [106]

Answer:

I would answer but I cannot see it sorry :D

Step-by-step explanation:

7 0
3 years ago
The recommended dosage for ceclor (cefaclor) is 30mg/kg to be given P.O. for a child weighing 32 lbs. Available: 125mg/5ml. How
andreyandreev [35.5K]

The child's weight in kilogram (kg) is equal to 14.5 kilogram. 2. The safe 24-hour dosage range for this child is 290 mg to 580 mg.

Given that the recommended dosage for ceclor is 30mg/kg to be given P.O. for a child weighing 32 lbs.

In order to determine the weight of the child, we would convert the value of the child's weight in pounds (lbs) to kilogram (kg) as follows:

1 pound = 0.4536 kilogram

32 pound = x kilogram

Cross-multiplying, we have: X = 32 × 0.4536 Child's weight, x = 14.5 kilogram.

Minimum range = 30 × 14.5 = 290 mg to 580 mg

Maximum range = 125 × 14.5 = 580 mg

Therefore, the safe 24-hour dosage range for this child is 290 mg to 580 mg.

Hence based on the calculations, we can infer and logically deduce that yes the dosage ordered safe because the safe single dose range is from 97 mg to 193 mg.

learn more about safe dosage at brainly.com/question/13186642

#SPJ9

Complete Question:

Ceclor (cefaclor) 100 mg p.oh is ordered for a child weighing 32 lbs.

1. What is the child's weight in kilograms (round to tenths)

2. What is safe 24-hour dosage range for this child?

3. Is the dosage ordered safe?

A. Yes

B. No, below the recommended dosage

C. No, it is for above the recommended dosage

D. More information is needed

4 0
1 year ago
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