1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alla [95]
3 years ago
8

Joe is 20 years old. His sister is half his age less 7. How old is his sister?

Mathematics
1 answer:
MakcuM [25]3 years ago
3 0
The answer is 3. 20/2=10 10-7=3
You might be interested in
Use the net to find the lateral area of the prism.
salantis [7]
The lateral area is represented in the diagram by a rectangle 11 cm wide and
(8 + 15 + 17) cm = 40 cm long.

The lateral area is 
   (11 cm)*(40 cm) = 440 cm²
6 0
3 years ago
Assume that the sales of a certain appliance dealer can be approximaed y sraig were $6000 in 1982 and $ 64,000 in 1987. Let x -
viktelen [127]

Answer:

y=11,600x+6,000

Yearly sales in 1990: $98,800.

Step-by-step explanation:

We have been given that the sales of a certain appliance dealer can be approximated by a straight line. Sales were $6000 in 1982 and $ 64,000 in 1987.

If at 1982, x=0 then at 1987 x will be 5.

Now, we have two points (0,6000) and (5,64000).

\text{Slope}=\frac{64,000-6,000}{5-0}

\text{Slope}=\frac{58,000}{5}

\text{Slope}=11,600

Now, we will represent this information in slope-intercept form of equation.

y=mx+b, where,

m = Slope,

b = Initial value or y-intercept.

We have been given that at x=0, the value of y is 6,000, so it will be y-intercept.

Substitute values:

y=11,600x+6,000

Therefore, the equation S=11,600x+6,000 represents yearly sales.

Now, we will find difference between 1990 and 1982.

1990-1982=8

To find yearly sales in 1990, we will substitute x=8 in the equation.

S=11,600(8)+6,000

S=92,800+6,000

S=98,800

Therefore, the yearly sales in 1990 would be $98,800.

6 0
3 years ago
Two trucks started toward each other at the same time from towns 500 km apart. One truck traveled at a rate of 65 km per hour wh
ale4655 [162]
They met after (4 hours).
(60+65)*x=500<span />
5 0
3 years ago
Simplify the expression.
Mashcka [7]

Answer:

-2.5

Step-by-step explanation:

-0.25x-6-5.5x-8.4=0

-5.75x-14.4=0

-5.75x=14.4

x= -2.5

3 0
3 years ago
Rachel runs 4 miles in 23 minutes. How many miles does she run per minute?​
KIM [24]

Answer:

To calculate how many total miles Rachel runs per minute, setting up a unit rate, that is a rate with a denominator of 1, would be helpful.

Step-by-step explanation:

Use the current problem to determine a rate.

23 minutes/4 miles

Now, set up a unit rate.

1 minute/<em>x </em>miles = 23 minutes/4 miles

To solve for <em>x, </em>we can use simple division strategies. We divide 23 by 23 to receive 1 minute. Likewise, dividing the current milage by 23 would wield the correct unit rate. To do this, divide 4 by 23.

4/23 = 0.1739130434782609

Finally, simplify your answer to receive 0.17.

Therefore, Rachel runs ~0.17 miles per minute. (Note that this answer is only a rounded answer of her actual milage per minute)

8 0
3 years ago
Other questions:
  • Explain how you can find 4times 754 using two different methods
    12·1 answer
  • Need help what is the answer ​
    7·1 answer
  • Help me please I don’t get it
    5·2 answers
  • FIRST TO ANSWER GETS BRAINLIEST
    6·2 answers
  • Evaluate the expression for the given value of x.<br><br> −6x + 5 for x= −6
    8·2 answers
  • Mrs. Okafor had $475 in her savings account. Each year, the value of the savings account increases
    6·1 answer
  • Can someone please help with these 2 questions? It would mean the world to me. I have attached the image for the questions.
    8·2 answers
  • Find wx? please help
    7·2 answers
  • Aidan buys 3 bicycles for $252. Each bicycle was the same price.
    6·2 answers
  • Which of these best represents the rate of change in the volume of the gas sample with respect to the temperature
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!