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hjlf
3 years ago
6

The LCM of 4 and 7 is____

Mathematics
2 answers:
topjm [15]3 years ago
4 0
28 is the LCM of 4 and 7
Zielflug [23.3K]3 years ago
4 0
The LCM of 4 && 7 is 28!!
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1/2-(-1/3)<br><br> Does anyone know the answer to this question?
Alexxx [7]

Answer:

5/6

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4 0
3 years ago
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The cost of renting a bus for a field trip was split evenly among 20 students. At the last minute, 10 more students joined the t
dexar [7]

By solving a linear equation, we will see that the total cost for renting the bus is $90.

<h3>What was the total cost of renting the bus, in dollars?</h3>

Let's say that the total cost is C.

When there are 20 students, each student should pay:

p = C/20

When the other 10 students are added (for a total of 30) each student pays:

p' = C/30.

We know that the cost for each of the original 20 students decreased by $1.50, so:

p' = p - $1.50

Then we have 3 equations to work with:

p = C/20

p' = C/30.

p' = p - $1.50

Now we can replace the first and second equations into the third one:

C/30 = C/20 - $1.50

Now we can solve this linear equation for C:

C/20 - C/30 = $1.50

C*( 1/20 - 1/30) = $1.50

C*(30/600 - 20/600) = $1.50

C*(10/600) = $1.50

C*(1/60) = $1.50

C = 60*$1.50 = $90

So the total cost for renting the bus is $90.

If you want to learn more about linear equations:

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4 0
2 years ago
HELP!!!!!!!!!!!
erica [24]
Your answer would be (b.) because -2+-3=-5

3 0
3 years ago
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Suppose James randomly draws a card from a standard deck of 52 cards. He then places it back into the deck and draws a second ca
qwelly [4]

Answer:

1.92%

Step-by-step explanation:

The probability for first case, picking a queen out of deck, will be:

\frac{4}{52}

as there will be 4 queens in a deck, one of each suit.

For the second pick, the probability of picking a diamond card, will be:

\frac{13}{52}

here the total will remain 52 as he has replaced the first card and not kept it aside and there will be 13 cards in diamond suit (including the three face cards).

Thus the net probability for both cases will be:

P = \frac{4}{52}  * \frac{13}{52}\\ P = \frac{1}{52}\\ P = 0.01923\\P = 1.923\%\\\\P = 1.92\%

Thus total probability for the combined two cases will be 1.92%

7 0
3 years ago
Plsssssssssssssss help
Zepler [3.9K]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
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