Answer:
C.
Explanation:
It's becase of the gavitational pull of a star or sun
Answer:
.0027 M
Explanation:
We must calculate the threshold concentration of PO3−4 using Ksp and the given concentration of Ca2+:
Ca3(PO4)2(s)⇌3Ca2+(aq)+2PO3−4(aq)
Ksp=8.6×10−19=[Ca2+]3[PO3−4]2=(4.9×10−5M)3[PO3−4]2
[PO3−4]=0.0027 M
Greater than (less space = less room for the particles to bounce around in = bounce around faster (hits walls/each other more often) = greater pressure)
Answer:
Number of contraction cycles that could theoretically be fueled by the complete combustion of one mole of glucose is around 17
Explanation:
Energy released during the complete combustion of 1 mole glucose = 2870 kJ
Energy required/muscle contraction cycle = 67 kJ/contraction
Energy conversion efficiency = 39%
Actual amount of energy converted to contraction per mole of glucose is:

Total contraction cycles fueled by the above energy is:
