Consider a hypothetical reaction in which a and b are reactants and c and d are products. if 25 grams of a completely reacts wit
1 answer:
According to law of conservation of mass, the mass can neither be destroyed nor created in a chemical reaction. The mass of reactants and mass of products are equal in a chemical reaction.
The reaction between A and B (reactants) to form C and D (products) is given as:
The mass of A = (given)
The mass of B = (given)
The mass of reactant = mass of A + mass of B
Substituting the values:
The mass of reactant =
The mass of C =
Let the mass of D =
So, the mass of product = mass of C + mass of D
Substituting the values:
the mass of product =
According to law of conservation of mass:
the mass of reactant = the mass of product
Substituting the values,
Hence, the amount of D produced in the reaction is .
You might be interested in
Answer:
1.327 g Ag₂CrO₄
Explanation:
The reaction that takes place is:
- 2AgNO₃(aq) + K₂CrO₄(aq) → Ag₂CrO₄(s) + 2KNO₃(aq)
First we need to <em>identify the limiting reactant</em>:
We have:
- 0.20 M * 50.0 mL = 10 mmol of AgNO₃
- 0.10 M * 40.0 mL = 4 mmol of K₂CrO₄
If 4 mmol of K₂CrO₄ were to react completely, it would require (4*2) 8 mmol of AgNO₃. There's more than 8 mmol of AgNO₃ so AgNO₃ is the excess reactant. <em><u>That makes K₂CrO₄ the limiting reactant</u></em>.
Now we <u>calculate the mass of Ag₂CrO₄ formed</u>, using the <em>limiting reactant</em>:
- 4 mmol K₂CrO₄ *
= 1326.92 mg Ag₂CrO₄
- 1326.92 mg / 1000 = 1.327 g Ag₂CrO₄
Answer: 9.09 %
Explanation:
To calculate the percentage concentration by volume, we use the formula:
Volume of ethanol (solute) = 30 ml
Volume of water (solvent) = 300 ml
Volume of solution= volume of solute + volume of solution = 30+ 300 = 330 ml
Putting values in above equation, we get:
Hence, the volume percent of solution will be 9.09 %.