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WINSTONCH [101]
2 years ago
15

How is a mixture different from a compound?

Chemistry
2 answers:
kakasveta [241]2 years ago
6 0

Answer:

I think the answer is d. Each substance in a mixture keeps most of its characteristic properties.

never [62]2 years ago
3 0

Answer:

C

Explanation:

Compounds are formed because of chemical bonding between two elements and Mixtures are formed when substances are physically mixed with one another. A mixture contains two or more types of pure substances (elements or compounds) moved physically not chemically; they do not contain any atomic bonds.

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What’s that’s balanced out
stiks02 [169]
Blank 1: nothing (to keep 2 total nitrogen)
blank 2: 3 (to make 6 total hydrogen)
blank 3: 2 (to make 2 total nitrogen and 6 total hydrogen)

hope this helps!! :)
7 0
3 years ago
Which of the following statements is not a description of asteroids?
seraphim [82]

Answer: Most of them lie in a belt between Earth and Mars.

Explanation:

Asteroids are small rocky bodies having irregular shape size which orbit sun. Majority of the asteroids are found in a belt between orbits of Mars and Jupiter. Scientists presume that these asteroids are remains of a planet that never formed between Mars and Jupiter due to great gravitational pull of the largest planet of the solar -system - Jupiter.

Thus, the incorrect description of the asteroids is: Most of them lie in a belt between Earth and Mars.

6 0
3 years ago
Read 2 more answers
Brainly is so boring like upgrade it to be better or something
Nikitich [7]

Answer:

ya same here i hope so btw

7 0
3 years ago
The standard enthalpy of formation for glucose [c6h12o6(s)] is −1273.3 kj/mol. what is the correct formation equation correspond
balu736 [363]
The standard formation equation for glucose C6H12O6(s) that corresponds to the standard enthalpy of formation or enthalpy change ΔH°f = -1273.3 kJ/mol is 
     C(s) + H2(g) + O2(g) → C6H12O6(s)
and the balanced chemical equation is 
     6C(s) + 6H2(g) + 3O2(g) → C6H12O6(s)

Using the equation for the standard enthalpy change of formation 
     ΔHoreaction = ∑ΔHof(products)−∑ΔHof(Reactants)
     ΔHoreaction = ΔHfo[C6H12O6(s)] - {ΔHfo[C(s, graphite) + ΔHfo[H2(g)] + ΔHfo[O2(g)]}

C(s), H2(g), and O2(g) each have a standard enthalpy of formation equal to 0 since they are in their most stable forms:
     ΔHoreaction = [1*-1273.3] - [(6*0) + (6*0) + (3*0)]
                           = -1273.3 - (0 + 0 + 0)
                           = -1273.3
8 0
3 years ago
Relative to electrons and electron states, what does each of the four quantum numbers specify
Alla [95]

Answer:

(n, l, m sub l, m sub s)

N: principle quantum number (1,2,3,4,etc)

l: angular momentum quantum number, the shape (l has to be at least 1 less than n, but can be 0 depending on n)

M sub l: magnetic quantum number (l determines this number)

M sub s: spin quantum number (can only ever be 1/2 or -1/2)

Explanation:

8 0
3 years ago
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