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WINSTONCH [101]
2 years ago
15

How is a mixture different from a compound?

Chemistry
2 answers:
kakasveta [241]2 years ago
6 0

Answer:

I think the answer is d. Each substance in a mixture keeps most of its characteristic properties.

never [62]2 years ago
3 0

Answer:

C

Explanation:

Compounds are formed because of chemical bonding between two elements and Mixtures are formed when substances are physically mixed with one another. A mixture contains two or more types of pure substances (elements or compounds) moved physically not chemically; they do not contain any atomic bonds.

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How much work is done if an object moves 4.5 m in has 12 Newtons of force on it
Cloud [144]

The formula of work is Work (Joules)=Force (Newtons) · distance in the direction of the force (meters), therefore its just a matter of replacing factors.

Work done = 12 · 4.5= 54 joules

4 0
3 years ago
Which would you expect to have higher enthalpy of fusion, N2 or I2? Explain your choice.
r-ruslan [8.4K]
The enthalpy of fusion of a substance is the energy required to change the state of a substance from solid to liquid at a constant temperature. The enthalpy of fusion for iodine, I₂, will be higher. This is because there are stronger intermolecular forces holding the iodine molecules together. The stronger intermolecular forces arise from the fact that iodine is a much larger molecule, so it has much more electrons resulting in higher Van der Waal's forces. This is also visible in the fact that at room temperature, iodine is a solid while nitrogen is a gas.<span />
5 0
3 years ago
A cell has a standard emf of + 0.135 v at 298 k. part a what is the value of the equilibrium constant for the cell reaction if n
Irina-Kira [14]
To look for the value of the equilibrium constant for the cell where n=1, it is computed by:
Eo = RT / nF * ln(K) 
(Eo * nF) /RT = ln(K) 
(0.135 * 1mol* e- * 9.65E4C/mol*e) / (8.314J / molK * 298K) = ln(K) 
10.52 = lnK 
e^10.52 = e ^ lnK 
K = e ^263/25
K = 37049.12 is the answer. 
4 0
3 years ago
Please balance the equation C7H16 + CoF3 = C7F16 + HF +CoF2
PIT_PIT [208]
haiaoaosoakaoaaonznskepwoa
5 0
3 years ago
How many atoms of Oxygen (O) are there in the products of the following equation:
jasenka [17]

Answer:

We can say, there are 4 mol of oxygen with (4 . NA) = 2.40ₓ10²⁴ atoms

Or just, 4 atoms oxygen.

Explanation:

CH₄  +  2O₂  →  CO₂  +  2H₂O

1 mol of methane reacts with 2 mol of oxygen to produce 1 mol of carbon dioxide and 2 mol of water.

We count in 1 mol of CO₂, we have 2 mol of oxygen

In 2 mol of water, we have 2 mol of oxygen.

We can say, there are 4 mol of oxygen with (4 . NA) = 2.40ₓ10²⁴ atoms

Or just, 4 atoms oxygen.

6 0
4 years ago
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