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2 years ago

Identify the period midline and amplitude of the following cosine function graph?

Mathematics

1 answer:

UNO [17]2 years ago

5 0

According to the graph: midline is 2; amplitude is 3; period is 120°.

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What is the measure of ZL?

Elodia [21]

Answer: C

Step-by-step explanation:

Angles opposite congruent sides in a triangle are congruent.

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2 years ago

7^x^2=9^x <br>how do I solve this using logs

Rina8888 [55]

Apply lg on both sides.
lg7^x^2 = lg9^x
Bring the power forward.
x^2lg7 = xlg9
x^2/x = lg9/lg7
x = lg9/lg7 = 1.13

4 0

3 years ago

Please anwser

Black_prince [1.1K]

The answers are
M1 = 112°
M2 = 26°

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3 years ago

Consider the linear equation x- 3/2y = 2

Allisa [31]

Answer:

don't know

Step-by-step explanation:

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3 years ago

Point \blue{A}Astart color blue, A, end color blue is at \blue{(-4, 8)}(−4,8)start color blue, left parenthesis, minus, 4, comma

ASHA 777 [7]

Answer:

The coordinates of point B are (6,7).

Step-by-step explanation:

Given points are

Blue = A(-4,8)

Purple = M(1,7.5)

Green = B

It is given that point M is the midpoint of point A and B.

Let coordinates of points are (a,b).

Midpoint of two points is

$Midpoint=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})$

$M=(\dfrac{-4+a}{2},\dfrac{8+b}{2})$

Coordinates of midpoint are (1,7.5).

$(1,7.5)=(\dfrac{-4+a}{2},\dfrac{8+b}{2})$

On comparing both sides we get

$1=\dfrac{-4+a}{2}\Rightarrow 2=-4+a\Rightarrow a=6$

$7.5=\dfrac{8+b}{2}\Rightarrow 15=8+b\Rightarrow b=7$

Therefore, the coordinates of point B are (6,7).

6 0

3 years ago