Pls help will mark brainliest
1 answer:
You might be interested in
Answer: The 90% confidence interval for the population mean μ is between 82.85 and 85.15,
Step-by-step explanation:
When population standard deviation is not given ,The confidence interval population proportion is given by ( ):-
, where n= Sample size.
s= Sample standard deviation
= sample mean
t* = Critical t-value (Two-tailed)
As per given , we have
n= 64
Degree of freedom : df = n-1=63
s= 5.5
Significance level :
Two-tailed T-value for df = 63 and would be
(By t-distribution table)
i.e. t*= 1.669
The 90% confidence interval for the population mean μ would be
∴ The 90% confidence interval for the population mean μ is between 82.85 and 85.15,
Complete Question
A biologist reports a confidence interval of (3.5,4.9) when estimating the mean height (in centimeters) of a sample of seedlings. What is the estimated margin of error and the sample mean?
Answer:
The margin of error is
The sample mean is
Step-by-step explanation:
from the question we are told that
The upper limit is
The lower limit is
Generally the margin of error is mathematically represented as
Generally the sample mean is mathematically evaluated as
=>
=>