Answer:
A. The solutions are 
.
B. The factored form of the quadratic expression 
Step-by-step explanation:
A. To find the solutions to the quadratic equation 
you must:
The solutions are:
B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.
To factor 
:
First, multiply the constant in the polynomial by 
where is equal to -1.
Since both terms are perfect squares, factor using the difference of squares formula
Answer:
y = 0
Step-by-step explanation:
It is always a good idea to look at the question and make some observations about it. Here, you might observe ...
- all of the bases are powers of 3: 243 = 3^5; 9 = 3^2
- y is a factor of every exponent
The latter observation is important, because it means that when y=0, every exponential expression has a value of 1. Hence y = 0 is a solution.
__
To solve the equation, you can write it in terms of powers of 3.
(3^5)^(-y) = (3^-5)^(3y)·(3^2)^(-2y)
3^(-5y) = 3^(-15y)·3^(-4y)
3^(-5y) = 3^(-19y)
-5y = -19y . . . . . . . . equating exponents; equivalent to taking log base 3
14y = 0 . . . . . . . . . . add 19y
y = 0 . . . . . . . . . . . one solution
______
The rules of exponents we used are ...
(a^b)(a^c) = a^(b+c)
(a^b)^c = a^(bc)
1/a^b = a^-b
Your answer would be <span>30 m²!
: D</span>
Answer: 1
Step-by-step explanation: the probability mass function that defines a possion probability distribution is given below as
P(x=r) = e^-u × u^x/x!
For this question, x = 0 and u = 9.5
Hence we have that
P(x=0) = e^-0 × 9.5^0 / 0!
P(x=0) = 1 × 1/ 1 = 1
