From what i know, the feet of an animal should always be on the table. This is due to the fact that aside from health reason's, the animal usually feels more comfortable not on it's back.
Answer:
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Answer:
The correct answer is - 6.8950.61 gm per mole
Explanation:
Given:
One form of hemoglobin is 0.324% Fe by mass
1 hemoglobin = 4 Fe
Solution:
Molar Mass of iron = 55.85
mass of 4 iron atom = 55.85 * 4 = 223.4 gms
0.324 % correspond to 223.4 gms
100 % correspond to = 223.4 *100/0.324
= 68950.61 gm
MM of haemoglobin = 68950.61 gms = 6.8 E4 gms
Answer:
the animal cell will burst
Explanation:
If the salt solution in the animal cell is 30%, it means the water is at a 70% concentration. Outside is 20%, so the water is 80%.
Water will enter the cell. Water is at a higher concentration outside the cell (80%) or a lower concentration inside the cell (70%) by the process of osmosis.
Eventually, the animal cell will burst, because it does not have any cell wall to control the swelling of the cell that occurs as water flows in.
Answer:
2% of the progeny will be double crossovers for the trihybrid test cross
Explanation:
By knowing the positions of genes, we can estimate the distances in MU between them per region.
- Genes A and B are 10 map units apart (Region I)
- Genes B and C are 20 map units apart (Region II)
- Genes A and C are 30 map units apart
----A-------10MU--------B-------------20MU-------------C---
Region I Region II
We can estimate the recombination frequencies by dividing each distance by 100.
• recombination frequency of A-B region = 10MU / 100 = 0.10
• recombination frequency of B-C region = 20MU / 100 = 0.20
Now that we know the recombination frequencies in each region, we can calculate the expected double recombinant frequency, EDRF, like this:
EDRF = recombination frequency in region I x recombination frequency in region II.
EDRF = 0.10 x 0.20 = 0.02
2% of the progeny will be double crossovers for the trihybrid test cross
