In general, the average rate of change of f (x) on the interval a, b is given by f(b) – f(a) / b – a. The average rate of alteration of a function, f (x) on an interval is well-defined to be the variance of the function values at the endpoints of the interim divided by the difference in the x values at the endpoints of the interval. this is also known as the difference quotient that tells how on average, the y values of a function are changing in connection to variations in the x values. A positive or negative rate of change is applicable which match up to an increase or decrease in the y value among the two data points. It is called zero rate of change when a quantity does not change over time.
Answer:
In 3 years, the interest of a sum of rs 3600 at the rate of 5.5% per year be Rs 594.
Step-by-step explanation:
T = ?
R = 5.5%
P = Rs 3600
I = Rs 594
so
T = (I×100)/(P×R)
or, T = (594×100)/(3600×5.5)
or, T = 59400/19800
so, T = 3 yrs
Answer:
90%
Step-by-step explanation:
divide - 27/30
Answer:
m
Step-by-step explanation:
Let
Bas length of box=b
Height of box=h
Material used in constructing of box=36 square m
We have to find the height h and base length b of the box to maximize the volume of box.
Surface area of box=




Volume of box, V=
Substitute the values


Differentiate w. r.t b







The negative value of b is not possible because length cannot be negative.
Again differentiate w.r.t b

At

Hence, the volume of box is maximum at
.




m
Answer:
Step-by-step explanation:
Percentage without triazine resistance
Start 21,200%
End 9,900%
Percentage with triazine resistance
Start 28,800%
End 35,100%