Answer:
![x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]](https://tex.z-dn.net/?f=x%3D%28243%29log_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D)
Step-by-step explanation:
you have the following formula:
To solve this equation you use the following properties:
Thne, by using this propwerty in the equation (1) you obtain for x
![log_{(\frac{1}{81})}(\frac{1}{81})^{\frac{x}{243}}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\\frac{x}{243}=log_{\frac{1}{81}}[(\frac{1}{81})-1]\\\\x=(243)log_{\frac{1}{81}}[(\frac{1}{81})-1]](https://tex.z-dn.net/?f=log_%7B%28%5Cfrac%7B1%7D%7B81%7D%29%7D%28%5Cfrac%7B1%7D%7B81%7D%29%5E%7B%5Cfrac%7Bx%7D%7B243%7D%7D%3Dlog_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D%5C%5C%5C%5C%5Cfrac%7Bx%7D%7B243%7D%3Dlog_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D%5C%5C%5C%5Cx%3D%28243%29log_%7B%5Cfrac%7B1%7D%7B81%7D%7D%5B%28%5Cfrac%7B1%7D%7B81%7D%29-1%5D)
Answer:
The area of the warehouse floor is 1925yd²
The volume of the boxes is 4812.5yd³
Step-by-step explanation:
First we have to calculate the area, for this we must multiply the length by the width
a = area
l = long = 55yd
w = width = 35yd
a = l * w
a = 55yd * 35yd
a = 1925yd²
to calculate the volume we have to multiply the area by the height
asks us for the volume for half the height so we have to divide the height by 2
a = area = 1925yd²
h = height = 5yd/2 = 2.5yd
v = volume
v = a * h
v = 1925yd² * 2.5yd
v = 4812.5yd³
The area of the warehouse floor is 1925yd²
The volume of the boxes is 4812.5yd³
Answer:
If he spent 20 min. on math and on breaks then he'd spend 20 min. on the essay
Step-by-step explanation:
Answer:
7.3 in
Step-by-step explanation:
area = 27 = 54/2 = (x^2)/2
so what squared is 54?
7.34 whatever inches.
round it down, that's 7.3.
Answer:
she end
Step-by-step explanation:
bansnd
