Answer:
runtime error
Explanation:
Based on the information provided within the question it can be said that the line of code "System.out.println(resultSet.getString(1));" would not print out anything and instead would give you a runtime error. This is because there is no resultSet.next() line in your code allowing for the resultSet to start in the first row and move consequently down the rows. Thus giving a runtime error.
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Answer:
24 is the answer hope that helped!
•w•
Answer:
D is my answer to this question.
<span>Artificial selection :)</span>
He is using a Computer to type out the document, and a Printer for printing the document.
Thank you!