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koban [17]
3 years ago
10

5th GRADE MATH! Select the statement that correctly compares two numbers. A. 6,092 > 6,092.001 B. 6,197.02 > 6,197.2 .C 6,

232.01 = 6,232.1 D. 6,365.1 < 6,365.999
Mathematics
2 answers:
Lilit [14]3 years ago
7 0

Answer:

D is correct

Step-by-step explanation:

A is incorrect because the lesser than is .001 higher

B is wrong since is .18 higher

C is wrong because its not equalone is .9 higher

nlexa [21]3 years ago
6 0

Answer:

D

Step-by-step explanation:

6365.1<6365.999

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TIMED QUESTION NEED HELP FASTWhat values of b satisfy 3(2b + 3)2 = 36?
egoroff_w [7]

Answer:

\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}

Step-by-step explanation:

3(2b+3)^{2}=36\\\frac{3(2b+3)^{2}}{3}=\frac{36}{3}\\(2b+3)^{2}=12

Taking square root both sides, we get

\sqrt{(2b+3)^{2}}=\pm \sqrt{12}\\2b+3=\pm \sqrt{4\times 3}\\2b+3=\pm 2\sqrt{3}\\2b+3-3=\pm 2\sqrt{3}-3\\2b=-3\pm 2\sqrt{3}\\b=\frac{-3\pm 2\sqrt{3}}{2}\\b=\frac{-3+ 2\sqrt{3}}{2}\textrm{ or }b=\frac{-3- 2\sqrt{3}}{2}

Therefore, the values of b are:

\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}

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4 years ago
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Answer:

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