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lord [1]
3 years ago
13

Kendra went on a shopping trip to Yardley. She purchased a cowboy hat originally priced at $25 but discounted 20%. If sales tax

in Yardley is 10%, what was the total cost?
Mathematics
1 answer:
STALIN [3.7K]3 years ago
8 0

Answer:

The total cost =$22

Step-by-step explanation:

Given the original price of the item is $25.

On this item there is a 20% discount which is 25*{\frac{20}{100}}=$5.

So the discounted price of the item is 25-5=$20.

Now sales tax is the amount paid by the retailer to the governing body from the money he received through the customer.

The retailer receives $20.

sales tax rate=10%

sales tax=20*{\frac{10}{100}=$2.

The total cost of the item=discounted price + sales tax=$20+$2=$22

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Answer:

∠Y = 55°

Step-by-step explanation:

Since triangle ABC and XYZ are congruent, that means that...

∠A = ∠X

∠B = ∠Y

∠C = ∠Z

Since ∠Y = ∠B and ∠B = 55°, that means ∠Y = 55°.

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3 years ago
Yesterday, Caitlin swam 20 laps in the pool. Hannah swam 4/5 as many laps As Caitlin. How many laps did Hannah swim?
Misha Larkins [42]

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1 year ago
2. Find the 20th term of an arithmetic sequence if its 6th term is 14 and 14th term is 6.
Fudgin [204]

Answer:

\sf t_{20}= 0

Step-by-step explanation:

<h3>Arithmetic sequence:</h3>

      \sf \boxed{\bf n^{th} \ term = a + (n-1)d}\\\\\text{Here, a is the first term ; d is the common difference }

6th term is 14 ⇒ \sf t_6 = 14

                a + (6 - 1)d = 14

                    a  +  5d = 14  --------------(I)

14th term is 6 ⇒\sf t_{14} = 6

             a + (14-1)d = 6

                  a + 13d = 6 ----------------(II)

Subtract equation (II) from equation(I)

        (I)          a + 5d = 14

        (II)         a + 13d = 6

                    <u>-    -          -</u>

                            -8d = 8

                               d  = 8 ÷(-8)      

                              \sf \boxed{\bf d= (-1)}

Plugin d = -1 in equation (I)

a + 5(-1) = 14

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             \sf \boxed{\bf a = 19}  

20th term:

 \sf t_{20}= 19 + 19*(-1)

       = 19 - 19

   \sf \boxed{\bf t_{20} = 0}

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