We are required in this problem to approximate tan α which <span>α is less than </span><span>20 degrees.
In radians 20degrees is equal to 0.349; find tan 0.349=0.363
percentage error=(0.349-.363)*100/(0.363) =-3 percent error so for largest angle 20 degrees , the error is less than 10 percent</span>
Momentum = mass x velocity
Mementum = 60 × 8
= 48 kg-m/s
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Are you referring the term Amplitude.
Answer:
Time period of the oscillation will be 0.695 sec
Explanation:
We have given mass attached to the string m = 0.350 kg
The spring is stretched by 0.120 m
So x = 0.120 m
We know that force is given by F = Kx
So mg = kx

k = 28.5833
Now time period is given by

So time period of the oscillation will be 0.695 sec
Complete Question
The complete question is shown on the first uploaded image
Answer:
The spring scale
reads 
Explanation:
From the question we are told that
The first force is 
The acceleration by which the cart moves to the right is 
The mass of the cart is m = 3.231 kg
Generally the net force on the cart is

This net force is mathematically represented as

So


