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Vadim26 [7]
3 years ago
10

You're bragging to your friend from Canada that your new hybrid car gets great gas mileage. You tell him you get 50 miles per ga

llon, and he says that's nothing: "I get 23 kilometers per liter in my new car". Does he actually get better gas mileage than you
Physics
1 answer:
Zarrin [17]3 years ago
6 0

(23 km/L) · (3.785 L/gallon) · (1 mile/1.609344 km) =

(23 · 3.785 · 1 / 1.609) · (km · Liter · mile) / (Liter · gallon · km) =

54.1 mile/gallon .

The Canadian's car is more fuel efficient than your car is.  

This should not surprise you.  The average cost of gasoline in Canada right now (October 2018) is a little over USD3.80 a gallon, compared to $2.60 in the US.

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In physics it is important to use mathematical approximations. Demonstrate that for small angles (< 20°) the following relati
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In radians 20degrees is equal to 0.349; find tan 0.349=0.363
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A 60 kg zebra is traveling 8 m/s east. What is the zebra’s momentum? kg-m/s
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Momentum = mass x velocity

Mementum = 60 × 8

= 48 kg-m/s


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3 years ago
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What tern is used to describe the measurement of a wave equal to half the distance from crest to trough?
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Are you referring the term Amplitude.
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4 years ago
When a mass of 0.350 kg is attached to a vertical spring and lowered slowly, the spring stretches 0.120 m. The mass is now displ
AURORKA [14]

Answer:

Time period of the oscillation will be 0.695 sec

Explanation:

We have given mass attached to the string m = 0.350 kg

The spring is stretched by 0.120 m

So x = 0.120 m

We know that force is given by F = Kx

So mg = kx

0.350\times 9.8=k\times 0.120

k = 28.5833

Now time period is given by

T=2\pi \sqrt{\frac{m}{k}}=2\times 3.14\sqrt{\frac{0.35}{28.5833}}=0.695sec

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6 0
3 years ago
The cart now moves toward the right with an acceleration toward the right of 2.50 m/s2. What does spring scale Fz read? Show you
katrin2010 [14]

Complete Question

The  complete question is shown on the first uploaded image

Answer:

The spring scale F_2 reads  F_2 =  2.4225 \ N

Explanation:

From the question we are told that

      The first force is  F_1  =  10.5 \ N

      The acceleration by which the cart moves to the right is  a = 2.50  \ m/s^2

      The mass of the cart is  m  = 3.231  kg

       

Generally the net force on the cart is  

       F_{net} = F_1 -  F_2

This net force is mathematically represented as

      F_{net} =  m * a

So  

        m*  a =  10 - F_2

        F_2 =  10.5 -  2.5 (3.231)

        F_2 =  2.4225 \ N

 

3 0
3 years ago
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