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fenix001 [56]
4 years ago
7

In physics it is important to use mathematical approximations. Demonstrate that for small angles (< 20°) the following relati

onship is true where α is in radians and α' is in degrees.
Use a calculator to find the largest angle for which tan α may be approximated by α with an error less than 10.0%.
Physics
2 answers:
Olenka [21]4 years ago
8 0
We are required in this problem to approximate tan α which <span>α is less than </span><span>20 degrees.
In radians 20degrees is equal to 0.349; find tan 0.349=0.363
 percentage error=(0.349-.363)*100/(0.363) =-3 percent error so for largest angle 20 degrees , the error is less than 10 percent</span>
mihalych1998 [28]4 years ago
5 0

Answer:

\alpha = 30.9 degree

Explanation:

percentage error of approximation is less than 10%

so we will have

error = \frac{tan\alpha - \alpha}{tan\alpha} \times 100

now we will have

10 = \frac{tan\alpha - \alpha}{tan\alpha} \times 100

0.1 = \frac{tan\alpha - \alpha}{tan\alpha}

now we have

0.1 tan\alpha = tan\alpha - \alpha

0.9 tan\aplha = \alpha

so here we have

\alpha = 30.9 degree

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c . slower and started moving in place.

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Matter can exist generally in three phases, as a solid, liquid or gas. But it can be transformed from one phase to another by the removal or application of heat energy.

The water was initially in a liquid form in the sealed tank until energy was transferred out of the substance. Thus, this causes a change of state in which the water turns to a solid. Whereby during the process, the molecules of the water moved slowly until they are fixed at a point, and vibrates individually at their individual point.

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The nucleus of the atom contains 8 protons and 9 neutrons. The atom is electrically
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A cheetah starts from rest and accelerated at 8.7 m/s^2 for 3s. How far did the cheetah go in that time
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3 years ago
A tank, shaped like a cone has height 6 meters and base radius 5 meters long. It is placed so that the circular part is upward.
AlekseyPX

The work required to pump out the liquid is 2.35 MJ.

What is work?

Work can be defined as the scalar product of the force and the displacement.

The formula to calculate the work done W is,

W=F.d

where F is the force and d is the displacement.

Note: It is assumed that the weight of one cubic unit of the liquid is 10000 \text{ N/m}^3.

Break down the vertical tank into parallel disc elements whose thickness is dh and are located at a height h from the ground. The radius of the element at height h is r.

It is given that the height of the tank is 6 m and the base radius is 5 meters. Using these, the ratio of the radius r at height h to the height h by using the triangle similarity criterion is,

\frac{h}{r}=\frac{6}{5} \\ r=\frac{5h}{6}

Using the above value of r, the volume of the element is given by,

V= \pi r^2dh\\V=\pi (\frac{5h}{6})^2dh\\V= \frac{25\pi h^2}{36} dh

The weight of the volume element is the force required.

The weight of one cubic unit of the liquid is 10000 \text{ N/m}^3.

So the weight F of the volume element at height h is given by,

F=10000 (\frac{25 \pi h^2}{ 36})dh\\F= 6944.44\pi h^2dh

At the height h, the difference in the height of the top of the tank and the volume element is (6-h). So the work required to pump out the volume of liquid at height h is given by the integrating the equation,

W=6944.44\pi\int\limits^6_0 {(6h^2-h^3)} \, dx \\\\W=69.44\pi \left[ 2h^3-\frac{h^4}{4}\right]^6_0\\W=2,.35\times10^6\text{ J}

The value of the W obtained is 2.35*10^6 J or 2.35 MJ.

Learn more about work here:

brainly.com/question/16627899

#SPJ4

8 0
2 years ago
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