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Tems11 [23]
3 years ago
7

A 1500 kg car traveling at 15.0 m/s to the south collides with a 4500 kg truck that is at rest at a stopligt. The car comes to a

stop but imparts all it’s mometum to the truck. How fast is the truck moving after the collision and in which direction? (Hint: this is an elastic collision)
Physics
1 answer:
Arlecino [84]3 years ago
5 0

Answer:

<em><u>M</u></em><em><u>a</u></em><em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u>m</u></em><em><u>a</u></em><em><u>t</u></em><em><u>i</u></em><em><u>c</u></em><em><u>a</u></em><em><u>l</u></em><em><u>l</u></em><em><u>y</u></em><em><u>:</u></em>

That will be

<em>=</em><em> </em><em>1</em><em>5</em><em>0</em><em>0</em><em> </em><em>x</em><em> </em><em>1</em><em>5</em><em> </em><em>x</em><em> </em><em>4</em><em>5</em><em>0</em><em>0</em>

<em>=</em><em> </em><em><u>1</u></em><em><u>0</u></em><em><u>1</u></em><em><u>,</u></em><em><u>2</u></em><em><u>5</u></em><em><u>0</u></em><em><u>,</u></em><em><u>0</u></em><em><u>0</u></em><em><u>0</u></em>

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What is the net force on a bag pulled down by gravity with a force of 18 newtons and pulled upward by a rope with a force of 18
VARVARA [1.3K]

Answer:

0 N.

Explanation:

Force: This can be defined as the product of mass and the acceleration of the body. The S.I unit of force is Newton (N).

The expression of net force when both force act in the different direction is given as

F' = W-F ........................ Equation 1

Where F' = Net force on the bag, W = gravitational force on the bag, F = Force acting upward on the bag

Given: W = 18 N, F = 18 N.

Substitute into equation 1

F' = 18-18

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If Weight=mg and Force=ma, and the only force acting on an object is gravity, then the masses cancel each other out and you are
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When g=a, that means everything on earth fall at the same rate.

<h3>Why does everything fall to the earth at the same rate?</h3>

As such, all objects free fall at the same rate regardless of their mass. Because the 9.8 N/kg gravitational field at Earth's surface causes a 9.8 m/s/s acceleration of any object placed there, we often call this ratio the acceleration of gravity.

<h3>Why is gravity equal to acceleration?</h3>

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Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to de
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Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate <u>self-representation.</u>

<h3>Who is a leader?</h3>

A person taking the charge of the organization and leading a team under him is known as a leader.

"The complete question is"Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate _______________. An employee will display _______________ by adhering to professional standards of the workplace and encouraging co-workers to do the same."

Options:

First Blank: work ethic

First Blank: self-representation

First Blank: diversity awareness

Second Blank: leadership skills

Second Blank: nonverbal skills

Self-representation may be shown through dressing appropriately for diverse settings, speaking politely, and keeping up with personal cleanliness.

By upholding the workplace's ethical norms and encouraging others to do the same, an employee will demonstrate leadership qualities.

Dressing suitably for different situations, using appropriate language, and maintaining good personal hygiene are all ways to demonstrate <u>self-representation.</u>

<u></u>

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4 0
2 years ago
A gazelle leaps from a cliff 2.5 m high with a speed of 5.6m/s.
jeyben [28]

Initial speed of Gazelle is along x direction and its value will be

v_x = 5.6 m/s

also its initial height is given as

y = 2.5 m

Part a)

now from kinematics along Y direction

\Delta y = v_y t + \frac{1}{2} at^2

as we know that

\Delta y = 0

v_y = 0

a = 9.8 m/s^2

2.5 = 0 + \frac{1}{2} (9.8) t^2

t = 0.714 s

Part b)

distance moved horizontally

\Delta x = v_x t

as we know that

v_x = 5.6 m/s

now we will have

v_x = 5.6 (0.714) = 4m

so it will lend at distance of 4 m.

Part c)

final velocity in vertical direction

v_{fy} = v_y + at

v_{fy} = 0 + (9.8)(0.714) = 7 m/s

v_x = 5.6 m/s

so net speed will be

v^2 = v_x^2 + v_y^2

v^2 = 7^2 + 5.6^2

v = 8.96 m/s


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3 years ago
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