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3 years ago

Which is a longitudinal wave that requires a medium to move

Physics

2 answers:

jeka57 [31]3 years ago

5 0

Answer:

Longitudinal wave are those in which the motion of the particles is along the direction of the medium. It always requires the medium to travel.We can say that a wave that oscillates back and forth that means moving in same interval.

And sound is the longitudinal wave that requires a medium to move.

kifflom [539]3 years ago

5 0

Sound is a longitudinal wave which requires medium to move.

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Two electrons in a vacuum exert force of F = 3.8E-09 N on each other. They are then moved such that they are separated by x = 8.

iren [92.7K]

Answer:

F_n = 5.65E-11 N

d = 1.20682E-31 m

Explanation:

F = 3.8E-09 N

where

m = Mass of electron = 9.109E−31 kilograms

G = Gravitational constant = 6.67E-11 m³/kgs²

x = Distance between them

$F=G\frac{m^2}{x^2}\\\Rightarrow 3.8E-09=G\frac{m^2}{x^2}$

For $F_n$

$F_n=G\frac{m^2}{x^2}\\\Rightarrow F_n=G\frac{m^2}{(8.2x)^2}\\\Rightarrow F_n=G\frac{m^2}{67.24x^2}$

Dividing the above equations we get

$\frac{F}{F_n}=\frac{G\frac{m^2}{x^2}}{G\frac{m^2}{67.24x^2}}\\\Rightarrow \frac{F}{F_n}=67.24\\\Rightarrow F_n=\frac{F}{67.24}\\\Rightarrow F_n=\frac{3.8E-09}{67.24}\\\Rightarrow F_n=5.65E-11\ N$

F_n = 5.65E-11 N

$F=G\frac{m^2}{x^2}\\\Rightarrow x=\sqrt{\frac{Gm^2}{F}}\\\Rightarrow x=\sqrt{\frac{G}{F}}m\\\Rightarrow x=\sqrt{\frac{6.67E-11}{3.8E-09}}9.109E-31\\\Rightarrow x=1.20682E-31\ m$

d = 1.20682E-31 m

8 0

3 years ago

Help asap

n200080 [17]

Answer:

magma

Explanation:

I wanna think that that's right if it's not in so sorry but I'm pretty sure it's magma

6 0

2 years ago

A man is standing on the edge of a 20.0 m high cliff. He throws a rock horizontally with an initial velocity of 10.0 m/s. How lo

Arlecino [84]

Answer:

t = 4.08 s

R = 40.8 m

Explanation:

The question is asking us to solve for the time of flight and the range of the rock.

Let's start by finding the total time it takes for the rock to land on the ground. We can use this constant acceleration kinematic equation to solve for the displacement in the y-direction:

Δx = v_0 t + 1/2at²

We have these known variables:

(v_0)_y = 0 m/s
a_y = -9.8 m/s²
Δx_y = -20 m

And we are trying to solve for t (time). Therefore, we can plug these values into the equation and solve for t.

-20 = 0t + 1/2(-9.8)t²
-20 = 1/2(-9.8)t²
-20 = -4.9t²
t = 4.08 sec

The time it takes for the rock to reach the ground is 4.08 seconds.

Now we can use this time in order to solve for the displacement in the x-direction. We will be using the same equation, but this time it will be in terms of the x-direction.

List out known variables:

v_0 = 10 m/s
t = 4.08 s
a_x = 0 m/s

We are trying to solve for:

Δx_x = ?

By using the same equation, we can plug these known values into it and solve for Δx.

Δx = 10 * 4.08 + 1/2(0)(4.08)²
Δx = 10 * 4.08
Δx = 40.8 m

The rock lands 40.8 m from the base of the cliff.

7 0

2 years ago

Which kind of road surface is easier to see when driving at night, a pebbled uneven surface or a mirror smooth surface?

pshichka [43]

A pebbled, uneven road would be easier to see at night because it minimizes the reflection of light from car’s light coming in the opposite direction. It is difficult to see when driving on the rainy day because the roadway reflects light from cars coming in the opposite <span>directions.</span>

6 0

3 years ago

Two people walking on a sidewalk have the following

vova2212 [387]

Answer:

X2 is fasteer

x=0 will go to Xi

Explanation:

4 0

2 years ago